auto

css水平居中的几种方式

对着背影说爱祢 提交于 2019-11-26 13:05:57
1. 子元素为行内元素时,父元素使用 text-align: center; 实现子元素的水平居中; 2. 子元素为块级元素时,    2.1. 将子元素设置 margin-left:auto; margin-right:auto; 实现居中;    2.2. 将子元素设置 display: inline-block,然后使用text-align:center实现居中;    2.3. 根据父元素采用绝对定位,右移父元素宽度的一半,再左移自身宽度的一半; 3. 父元素使用flex布局,    3.1. 子元素无论是行内还是块级,采用 align-self: center; 实现水平居中;    3.2. 子元素无论是行内还是块级,采用 margin: 0 auto; 实现水平居中; 实例代码如下: <style> * {   margin: 0; }   .outer-box1{     width: 200px;     height: 200px;     border: 5px solid black;     /* 对父元素设置此样式,则其内的行内元素实现居中 */     text-align: center;     position: relative;   }   .box1{     width: 50px;     height: 50px;    

深入理解CSS溢出overflow(补上8月7日)

泄露秘密 提交于 2019-11-26 12:49:44
转载自: https://www.cnblogs.com/Renyi-Fan/p/9206860.html 深入理解CSS溢出overflow 目录 一、总结 一句话总结:overflow用于对溢出内容的处理。 1、overflow有哪5个常用参数,分别是什么意思? 二、深入理解CSS溢出overflow 前面的话 定义 属性 失效 应用 回到顶部 > 一、总结(点击显示或隐藏总结内容) 一句话总结:overflow用于对溢出内容的处理。 1、overflow有哪5个常用参数,分别是什么意思? visible | hidden | scroll | auto | inherit visible 元素的内容在元素框之外也可见 auto 如果内容被剪裁,则浏览器会显示滚动条以便查看其余的内容 scroll 元素的内容会在元素框的边界处剪裁,但浏览器会显示滚动条以便查看其余的内容 hidden 元素的内容会在元素框的边界处剪裁,并且超出剪裁区域的内容不可见 回到顶部 二、深入理解CSS溢出overflow 回到顶部 前面的话   当一个元素固定为某个特定大小,但内容在元素中放不下。此时就可以利用overflow属性来控制这种情况 定义 overflow溢出   值: visible | hidden | scroll | auto | inherit   初始值: visible  

CSS世界精选

﹥>﹥吖頭↗ 提交于 2019-11-26 12:43:43
目录 基本概念 流 块级元素和内联元素 width: auto 和 height: auto 外在盒子和内在盒子 css权重和超越`!important` 盒模型(盒尺寸) 内联盒模型 替换元素 盒模型四大金刚 content padding margin border 好基友`line-height`和`vertical-align` 字母 x 的角色 line-height vertical-align 流的破坏 `float`属性的特性 `clear`的作用和不足 BFC:块级格式化上下文 绝对定位`position: absolute` 层叠规则 层叠上下文 CSS3新增层叠上下文 弹性布局 网格布局 文本控制 `::first-letter` 应用实例 `text-transform` 应用 `word-spacing` 空格间隙 `white-space ` 空白处理 `text-align: justify`(本文重点例子!) 元素的显示与隐藏 元素隐藏方法总结: `display: none`与`visibility: hidden`的区别 基本概念 这些基本概念有些可能不易理解但却都很重要,如果看完还是很不理解的话需要自己谷歌或百度,网上关于这些概念的文章不少。 流 “流”又叫文档流,是css的一种基本定位和布局机制 。流是html的一种抽象概念

Should the trailing return type syntax style become the default for new C++11 programs? [closed]

自作多情 提交于 2019-11-26 12:14:25
C++11 supports a new function syntax: auto func_name(int x, int y) -> int; Currently this function would be declared as: int func_name(int x, int y); The new style does not seem to be widely adopted yet (say in the gcc stl) However, should this new style be preferred everywhere in new C++11-programs, or will it only be used when needed? Personally, I prefer the old style when possible, but a code-base with mixed styles looks pretty ugly. James McNellis There are certain cases where you must use a trailing return type. Most notably, a lambda return type, if specified, must be specified via a

How does generic lambda work in C++14?

倾然丶 夕夏残阳落幕 提交于 2019-11-26 12:09:58
How does generic lambda work ( auto keyword as an argument type) in C++14 standard? Is it based on C++ templates where for each different argument type compiler generates a new function with the same body but replaced types (compile-time polymorphism) or is it more similar to Java's generics (type erasure)? Code example: auto glambda = [](auto a) { return a; }; Andy Prowl Generic lambdas were introduced in C++14 . Simply, the closure type defined by the lambda expression will have a templated call operator rather than the regular, non-template call operator of C++11 's lambdas (of course, when

Does &#39;auto&#39; type assignments of a pointer in c++11 require &#39;*&#39;?

旧街凉风 提交于 2019-11-26 12:08:42
问题 Given my variable being a pointer, if I assign it to a variable of \"auto\" type, do I specify the \"*\" ? std::vector<MyClass> *getVector(); //returns populated vector //... std::vector<MyClass> *myvector = getVector(); //assume has n items in it auto newvar1 = myvector; // vs: auto *newvar2 = myvector; //goal is to behave like this assignment: std::vector<MyClass> *newvar3 = getVector(); I\'m a bit confused on how this auto works in c++11 (this is a new feature to c++11, right?) Update: I

微信推文无缝滚动是这样炼成的

耗尽温柔 提交于 2019-11-26 11:59:09
来源 | 般若无界 作者 | 舒欣 效果展示 前两天我收到策划妹子的请求,需要在微信公众号里面做一篇推文。这个推文和以往不同,需要有两张图片无缝拼接,并且下方图片可以滚动的效果。 这个效果目前用微信自带的编辑器是无法实现的,毕竟功能有限,而这个需求也相对要小众一些。不过这个效果是很不错的,在微信推文中浏览会让人耳目一新。 从上图可以看出,首先是一张海报,乍一看没什么,以为就是一张图片。当你用手指滑动屏幕看下面内容时,你会惊奇的发现海报下半部分的内容时是可以滚动的,而且滚动到最底部后海报又回到了最初的状态。是不是很神奇?下面小编我将带你一探究竟! 技术实现原理 之前我们技术部做过一个端午节的推文,和这个类似,只不过那个是上面滚动下面固定,而这个是反过来了。端午节的推文案例效果如下: 我仔细看了下源码,发现原理是类似的。这个技术的关键有两点,一是上下两张图要 无缝衔接 ,而且宽度要相同。 二是 图片固定区域滚动 ,下面的长图不能一开始全部显示出来,而是先显示开头的一部分,这一部分的高度是固定的。 下面的内容初始隐藏,只有通过滚动才会出现下面的内容。滚动到最下方的时候,会发现海报合上了,这里其实是一个障眼法,下方图片的底部正好是和顶部一样的图(只有文字提示不一样),这里对设计有特殊要求,第二种长图的顶部和底部的内容是要保持高度一致的,为了实现这个效果,好的设计是必不可少的

C++ auto keyword. Why is it magic?

偶尔善良 提交于 2019-11-26 11:46:24
问题 From all the material I used to learn C++, auto has always been a weird storage duration specifier that didn\'t serve any purpose. But just recently, I encountered code that used it as a type name in and of itself. Out of curiosity I tried it, and it assumes the type of whatever I happen to assign to it! Suddenly STL iterators and, well, anything at all that uses templates is 10 fold easier to write. It feels like I\'m using a \'fun\' language like Python. Where has this keyword been my whole

Can the use of C++11&#39;s &#39;auto&#39; improve performance?

杀马特。学长 韩版系。学妹 提交于 2019-11-26 11:45:07
问题 I can see why the auto type in C++11 improves correctness and maintainability. I\'ve read that it can also improve performance (Almost Always Auto by Herb Sutter), but I miss a good explanation. How can auto improve performance? Can anyone give an example? 回答1: auto can aid performance by avoiding silent implicit conversions . An example I find compelling is the following. std::map<Key, Val> m; // ... for (std::pair<Key, Val> const& item : m) { // do stuff } See the bug? Here we are, thinking

Why do lambda functions drop deduced return type reference by default?

倖福魔咒の 提交于 2019-11-26 11:29:39
问题 In C++14, why do lambda functions with a deduced return type drop references from the return type by default? IIUC, since C++14 lambda functions with a deduced return type (without an explicit trailing return type) have a return type of auto , which drops references (among other things). Why was this decision made? It seems to me like a gotcha to remove a reference when that\'s what your return statement returns. This behavior caused the following nasty bug for me: class Int { public: Int(int