auto

ios8 iOS Auto Layout

六月ゝ 毕业季﹏ 提交于 2019-12-01 15:23:17
引言: Auto Layout 是iOS6发布后引入的一个全新的布局特性,其目的是弥补以往autoresizing在布局方面的不足之处,以及未来面对更多尺寸适配时界面布局可以更好的适应. 要完全掌握 Auto Layout 是一件非常消耗精力的事情,需要大量的实践,并且在根本上面,理解其如何使用,如果要全面的介绍 Auto Layout 和使用场景估计几篇博文都介绍不完, 本文希望能将使用 Auto Layout 的重点和技巧以及注意事项,进行一个介绍.成为学习 Auto Layout 的一个导航文章. 参考资料: 1:iOS7.0 Xcode5 Auto Layout 备忘录 http://www.cnblogs.com/thefeelingofsimple/p/3316300.html 2:iOS 6 Auto Layout NSLayoutConstraint 界面布局 http://www.devdiv.com/iOS_6_Auto_Layout_NSLayoutConstraint_%E7%95%8C%E9%9D%A2%E5%B8%83%E5%B1%80-weblog-227936-13173.html 3:iOS 6 新特性 Auto Layout http://www.cocoachina.com/bbs/read.php?tid=116558 4:WWDC 2012

Replace auto keyword with deduced type (clang or VS2010)

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-01 15:18:14
Has anyone written a script, plugin, or executable that replaces each instance of 'auto' with the compiler-deduced type? I need to port some C++11 code that uses auto all over the place. Clang is my first candidate. Has anyone modified it to do something like this? An alternative is to parse the errors from a compiler as the expected type might be in the error output. I could -Dauto=int and possibly get back "could not convert std::vector<int>::iterator to 'int'" Unfortunately, this is impossible in the general case. Consider: template <typename T> void foo(T & t) { auto it = t.find(42); ... }

Replace auto keyword with deduced type (clang or VS2010)

时间秒杀一切 提交于 2019-12-01 14:09:00
问题 Has anyone written a script, plugin, or executable that replaces each instance of 'auto' with the compiler-deduced type? I need to port some C++11 code that uses auto all over the place. Clang is my first candidate. Has anyone modified it to do something like this? An alternative is to parse the errors from a compiler as the expected type might be in the error output. I could -Dauto=int and possibly get back "could not convert std::vector<int>::iterator to 'int'" 回答1: Unfortunately, this is

Const in auto type deduction

大兔子大兔子 提交于 2019-12-01 13:17:38
I am reading Effective modern C++ from Scott Meyers. Item 1 contains the following example: template<typename T> void f(T& param); // param is a reference int x = 27; // x is an int const int cx = x; // cx is a const int f(cx); // T is const int, // param's type is const int& In Item 3 appears the following example: Widget w; const Widget& cw = w; auto myWidget1 = cw; // auto type deduction: // myWidget1's type is Widget Based on Item 1 I expected myWidget1 's type to be const Widget . Am I missing something? In most cases auto follows the rules of template argument deduction: § 7.1.6.4 [dcl

(转)利用Auto ARIMA构建高性能时间序列模型(附Python和R代码)

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-01 12:31:59
转自: 原文标题:Build High Performance Time Series Models using Auto ARIMA in Python and R       作者:AISHWARYA SINGH;翻译:陈之炎;校对:丁楠雅 原文链接: https://www.analyticsvidhya.com/blog/2018/08/auto-arima-time-series-modeling-python-r /    简介 想象你现在有一个任务:根据已有的历史数据,预测下一代iPhone的价格,可使用的特征包括季度销售、月度支出以及苹果资产负债表上的一系列内容。作为一名数据科学家,你会把这个问题归类为哪一类问题?当然是时间序列建模。 从预测产品销售到估算家庭用电量,时间序列预测是任何数据科学家都应该知道——哪怕不是熟练掌握——的核心技能之一。你可以使用多种不同的方法进行时间序列预测,我们将在本文中讨论 Auto ARIMA ,它是最为有效的方法之一。 首先,我们来了解一下ARIMA的概念,然后再进入正题——Auto ARIMA。为了巩固概念,我们将使用一个数据集,并用Python和R实现它。 目录 一、什么是时间序列? 二、时间序列预测的方法 三、ARIMA简介 四、ARIMA实现步骤 五、为什么需要Auto ARIMA? 六、用Auto ARIMA实现案例

c++11新特性之auto和decltype 类型

帅比萌擦擦* 提交于 2019-12-01 12:24:30
c++11引入了类型推断定义符 auto和decltype auto用法如下 auto 变量名 1 = 表达式1,变量名2 = 表达式2,.......; 编译器会根据表达式结果推断出定义的变量的类型,并用表达式值进行初始化 auto忽略表达式的顶层const 和引用的const而指针底层const会保留 先看看前置知识吧 https://www.cnblogs.com/mch5201314/p/11566712.html https://www.cnblogs.com/mch5201314/p/11485800.html 如果只想定义变量而不让表达式初始化,就用deltype 用法decltype(表达式) 变量 = 表达式 下面弄个例子看看 #include<iostream> using namespace std; int n; double f(int n) { int s = 0; for(int i = 1;i <= n;i++) s += i; return s; } int main() { int i = 10,j,*p = &i,&r = i; const int ic = i,&cj = ic; decltype(f(5)) s;//double s decltype(i + 3.4) x = 9;//double x; decltype(ic + 3)

Const in auto type deduction

让人想犯罪 __ 提交于 2019-12-01 10:17:57
问题 I am reading Effective modern C++ from Scott Meyers. Item 1 contains the following example: template<typename T> void f(T& param); // param is a reference int x = 27; // x is an int const int cx = x; // cx is a const int f(cx); // T is const int, // param's type is const int& In Item 3 appears the following example: Widget w; const Widget& cw = w; auto myWidget1 = cw; // auto type deduction: // myWidget1's type is Widget Based on Item 1 I expected myWidget1 's type to be const Widget . Am I

shared_ptr

不羁的心 提交于 2019-12-01 07:58:17
原文: https://www.cnblogs.com/wangkeqin/p/9351191.html   c++中动态内存的管理是通过new和delete来完成的,只要保证new和delete的配对使用,是没有问题的。但是有时候我们会忘记释放内存,甚至有时候我们根本就不知道什么时候释放内存。特别时在多个线程间共享数据时,更难判断内存该何使释放。这种情况下就机器容易产生引用非法内存的指针。                                                                                                       为了更容易(同时也更安全的管)的使用动态内存,新的标准库(C++11)提供了两种智能指针(smart pointer)类型来管理动态对象。智能指针的行为类似于常规指针。重要的区别是它负责自动释放所指向的对象。新标准提供的这两种智能指针的区别在于管理底层指针的方式:shared_ptr允许多个指针指向同一个对象;unique_ptr则独占所指向的对象。标准库还定义了一个weak_ptr的伴随类,他是一种弱引用,指向shared_ptr所管理的对象。这三种类型都定义在memory头文件中。 初始化 sahred_ptr   智能指针的使用方式与普通指针类似。解引用一个智能指针返回它指向的对象

auto it = vector.begin() resulting type is not convertible to const_iterator

会有一股神秘感。 提交于 2019-12-01 06:40:53
Containers are required to provide an iterator type which is implicitly convertible to a const_iterator . Given this, I am trying to use auto to initialize an object via vector::begin() , and use that resulting object in std::distance where the RHS is a const_iterator . This isn't working. Here is a complete example: #include <cstdlib> #include <vector> #include <iterator> #include <iostream> typedef std::vector <char> Packet; typedef std::vector <Packet> Packets; template <typename Iter> Iter next_upto (Iter begin, Iter end, size_t n) { Iter ret = begin; for (; n > 0 && ret != end; ++ret, --n

Using functions that return placeholder types defined in another translation unit

岁酱吖の 提交于 2019-12-01 06:06:57
问题 I'm having some trouble understanding how the C++14 extension of the auto type-specifier described in N3638 can possibly be implemented, and what, exactly, is allowed. Specifically, one of the changes to the standard says, If the declared return type of the function contains a placeholder type, the return type of the function is deduced from return statements in the body of the function, if any. It is easy enough to see how this works when body of the function is in the same file as the