assignment-operator

compiler generated constructors [duplicate]

时光总嘲笑我的痴心妄想 提交于 2019-11-30 08:25:30
问题 This question already has answers here : Conditions for automatic generation of default/copy/move ctor and copy/move assignment operator? (3 answers) Closed 2 years ago . This is just a quick question to understand correctly what happens when you create a class with a constructor like this: class A { public: A() {} }; I know that no default constructor is generated since it is already defined but are copy and assignment constructors generated by the compiler or in other words do i need to

`x = y, z` comma assignment in JavaScript [duplicate]

丶灬走出姿态 提交于 2019-11-30 08:21:39
Possible Duplicate: Javascript syntax: what comma means? I came across the code while reading this article (do a Ctrl + F search for Andre Breton ): //function returning array of `umbrella` fibonacci numbers function Colette(umbrella) { var staircase = 0, galleons = 0, brigantines = 1, armada = [galleons, brigantines], bassoon; Array.prototype.embrace = [].push; while(2 + staircase++ < umbrella) { bassoon = galleons + brigantines; armada.embrace(brigantines = (galleons = brigantines, bassoon)); } return armada; } What does the x = (y = x, z) construct mean? Or more specifically, what does the

What is the Rule of Four (and a half)?

ε祈祈猫儿з 提交于 2019-11-30 06:54:07
For properly handling object copying, the rule of thumb is the Rule of Three . With C++11, move semantics are a thing, so instead it's the Rule of Five . However, in discussions around here and on the internet, I've also seen references to the Rule of Four (and a half) , which is a combination of the Rule of Five and the copy-and-swap idiom. So what exactly is the Rule of Four (and a half)? Which functions need to be implemented, and what should each function's body look like? Which function is the half? Are there any disadvantages or warnings for this approach, compared to the Rule of Five?

Reducing code duplication between operator= and the copy constructor

强颜欢笑 提交于 2019-11-30 06:46:13
问题 I have a class that requires a non-default copy constructor and assignment operator (it contains lists of pointers). Is there any general way to reduce the code duplication between the copy constructor and the assignment operator? 回答1: There's no "general way" for writing custom copy constructors and assignment operators that works in all cases. But there's an idiom called "copy-&-swap": class myclass { ... public: myclass(myclass const&); void swap(myclass & with); myclass& operator=(myclass

Why does virtual assignment behave differently than other virtual functions of the same signature?

痴心易碎 提交于 2019-11-30 04:42:36
While playing with implementing a virtual assignment operator I have ended with a funny behavior. It is not a compiler glitch, since g++ 4.1, 4.3 and VS 2005 share the same behavior. Basically, the virtual operator= behaves differently than any other virtual function with respect to the code that is actually being executed. struct Base { virtual Base& f( Base const & ) { std::cout << "Base::f(Base const &)" << std::endl; return *this; } virtual Base& operator=( Base const & ) { std::cout << "Base::operator=(Base const &)" << std::endl; return *this; } }; struct Derived : public Base { virtual

Checklist for writing copy constructor and assignment operator in C++

落爺英雄遲暮 提交于 2019-11-29 22:27:09
Please write a list of tasks that a copy constructor and assignment operator need to do in C++ to keep exception safety, avoid memory leaks etc. Luc Hermitte First be sure you really need to support copy. Most of the time it is not the case, and thus disabling both is the way to go. Sometimes, you'll still need to provide duplication on a class from a polymorphic hierarchy, in that case: disable the assignment operator, write a (protected?) copy constructor, and provide a virtual clone() function. Otherwise, in the case you are writing a value class, you're back into the land of the Orthogonal

C++ linked List assignment Operator

混江龙づ霸主 提交于 2019-11-29 18:19:46
Trying to build an assignment Operator for a single linked list class. I thought I built it correctly, but am still getting a memory leak. The class consists of a a First and Last variable. And then a Node structure. The Node structure looks like this: struct node { TYPE value; node * next; node * last; }; My Assignment Operator looks like this, it still has a memory leak queue& queue::operator=(const queue &rhs){ if(this == &rhs ){ node *ptr = first; node *temp; while(ptr != NULL){ temp = ptr; ptr = ptr->next; delete temp; // release the memory pointed to by temp } delete ptr; } else{ if (rhs

Is it bad form to call the default assignment operator from the copy constructor?

倾然丶 夕夏残阳落幕 提交于 2019-11-29 17:27:01
问题 Consider a class of which copies need to be made. The vast majority of the data elements in the copy must strictly reflect the original, however there are select few elements whose state is not to be preserved and need to be reinitialized . Is it bad form to call a default assignment operator from the copy constructor? The default assignment operator will behave well with Plain Old Data( int,double,char,short) as well user defined classes per their assignment operators. Pointers would need to

Derived class inherit base class assignment operator?

亡梦爱人 提交于 2019-11-29 16:07:56
It seems to me that Derived class don't inherit base class Assignment operator if Derived class inherit Base class assignment operator , can you please explain the following example In the following code I am overriding base class operator= in Derived, so that Derived class default assignment operator calls overloaded operator= #include <iostream> using namespace std; class Base { public: Base(int lx = 0):x(lx) { } virtual Base& operator=( const Base &rhs) { cout << "calling Assignment operator in Base" << endl; return *this; } private: int x; }; class Derived : public Base { public: Derived

What is the result of an assignment expression in C? [duplicate]

六月ゝ 毕业季﹏ 提交于 2019-11-29 13:10:53
问题 This question already has answers here : What does an assignment return? (5 answers) Closed 8 months ago . In the following code: int c; while((c=10)>0) What does c = 10 evaluate to? Is it 1 which indicates that the value 10 is assigned to variable c successfully, or is it 10? Why? 回答1: c = 10 is an expression returning 10 which also assigns 10 to c. 回答2: Assignment returns with the assigned value. In case c=10 is 10. Since 10!=0, in c it means also true so this is an infinite loop. It is