arraylist

数组和集合的区别?

删除回忆录丶 提交于 2019-12-14 15:31:08
区别 :(长度,内容,元素,执行效率) 1、数组声明了它容纳的元素的类型,而集合不声明。 2、数组是静态的,一个数组实例具有固定的大小,一旦创建了就无法改变容量了。而集合大小不固定,是可以动态扩展容量的,可以根据需要动态改变大小,集合提供更多的成员方法,能满足更多的需求。若程序时不知道究竟需要多少对象,需要在空间不足时自动扩增容量,则需要使用容器类库,array不适用。 3、数组是java语言中内置的数据类型,是线性排列的,执行效率或者类型检查(不懂),都是最快的,ArrayList就是基于数组创建的容器类 4、数组存放的数据类型只能是一种(基本数据类型和引用数据类型),集合存放的类型可以不是一种,默认是Object类型 联系 :(转换方法) 1、使用相应的toArray()和Arrays.asList()方法可以互相转换。 集合的体系结构 : 集合体系中最主要的三个接口是List、Set、Map., Collection 下是list 和 set,Map也属于集合系统,但是和Collection接口不同 Set(不可重复)下是HashSet和TreeSet两个主要的实现类,Set 只能通过游标来取值,并且值是不能重复的 List(有序且元素可重复)下是ArrayList(线程不安全,底层基于数组)、Vector(线程安全,底层基于数组)。LinkedList(线程不安全

ArrayList 集合 简单运用

倖福魔咒の 提交于 2019-12-14 09:48:24
集合 遍历 import java.util.ArrayList; class Demo02 { public static void main(String[] args) { // 创建ArrayList集合 ArrayList<Integer> list = new ArrayList<Integer>(); // 向集合中添加元素(对象名.方法名(实参列表);) list.add(1); list.add(2); list.add(3); list.add(4); //获取单个的值 int n1=list.get(0); int n2=list.get(1); int n3=list.get(2); int n4=list.get(3); // 获取集合中元素的个数 System.out.println("集合的长度:" + list.size()); // 取出并打印指定位置的元素 for(int i=0;i<list.size();i++){ System.out.println("第"+(i+1)+"个元素是:" + list.get(i)); } } } 来源: https://www.cnblogs.com/l1314/p/12038168.html

ArrayList集合

被刻印的时光 ゝ 提交于 2019-12-14 09:35:45
导包:import java.util.ArrayList; 创建对象:与其他普通的引用数据类型创建方式完全相同,但是要指定容器中存储的数据类型: ArrayList<要存储元素的数据类型> 变量名 = new ArrayList<要存储元素的数据类型>(); 1. 集合中存储的元素,只能为<>括号中指定的数据类型元素; 2. “<要存储元素的数据类型>”中的数据类型必须是引用数据类型,不能是基本数据类型; //存储String类型的元素 ArrayList<String> list = new ArrayList<String>(); //存储int类型的数据 ArrayList<Integer> list = new ArrayList<Integer>(); //存储Phone类型的数据 ArrayList<Phone> list = new ArrayList<Phone>(); 8种基本数据类型所对应的引用数据类型表示形式: 基本数据类型 对应的引用数据类型表示形式 byte Byte short Short int Integer long Long float Float double Double char Character boolean Boolean 常用方法 方法声明 功能描述 boolean add (Object obj )

深入理解ArrayList

只谈情不闲聊 提交于 2019-12-14 07:13:58
什么是ArrayList? ArrayList的实现原理其实就是数组(动态数组),ArrayList的介绍及简单使用方法 动态数组与一般数组有什么区别? 与Java中的数组相比,ArrayList的容量能动态地增长 ArrayList效率怎么样? ArrayList不是线程安全的,所以效率比较高 ,但是只能用于单线程的环境中,那多线程呢?别急,文末会讲到 ArrayList主要继承哪些类实现了哪些接口? ArrayList主要继承了AbstractList类,实现了List、RandomAccess、Cloneable、Serializable接口 public class ArrayList<E> extends AbstractList<E> implements List<E>, RandomAccess, Cloneable, java.io.Serializable RandomAccess的意思是其拥有快速访问的能力,ArrayList可以以 O(1)[^1]的时间复杂度去根据下标访问元素。由于ArrayList底层结构是数组,所以它占据了一块连续的内存空间,其长度就是数组的大小,因此它也有数组的缺点,在空间效率不高,但是也有它的优点,就是查询速度快,时间效率较快 ArrayList的常量与变量有哪些? // 序列ID private static final long

How to get the arraylist out android studio

大憨熊 提交于 2019-12-14 04:23:05
问题 I am unable to get my ArrayList out when it's on a different page. I would like to get the ArrayList out Android Studio. This is CartActivity class: public class CartActivity extends AppCompatActivity { private ArrayList<CartItem> cartList; ListView listView; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_cart); listView = (ListView) findViewById(R.id.listView); CartAdapter adapter = null; cartList = new

JAVA ArrayList cant find element via indexOf() [duplicate]

限于喜欢 提交于 2019-12-14 04:14:45
问题 This question already has answers here : Java ArrayList IndexOf - Finding Object Index (4 answers) Closed 2 years ago . Im writing a short program and I have a problem. There is a problem with more details. I have function public CardStck from(Card card) int pos = this.cardList.indexOf(card); card for this example is Card(value=5, color="D")- as u see on the debugging screen Even there is that card im searching for 5(D) (diamond 5 card) in this.cardList the value of pos is -1 (not found)

Java - Slice any array at steps

本小妞迷上赌 提交于 2019-12-14 03:54:57
问题 In python we are able to do the following: array = [0,1,2,3,4,5,6,7,8,9,10] new_array= array[::3] print(new_array) >>>[0,3,6,9] Is there an equivalent to this in Java? I have been looking for this type of array slicing, but I have had no luck. Any help would be great, Thanks! 回答1: If you are using Java 8, then you can make use of streams and do the following: int [] a = new int [] {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; // filter out all indices that evenly divide 3 int [] sliceArr = IntStream

How to convert nested ArrayList in Array?

有些话、适合烂在心里 提交于 2019-12-14 03:53:47
问题 I have to convert an ArrayList of ArrayList in to Array. List<List<TockaXY>> clustersPorazdeljeni = new ArrayList<>(centers.size()); I know that is possible to convert a single ArrayList to Array like TockaXY[] arrayOfClusters = clustersPorazdeljeni.toArray(new TockaXY[centers.size()]); But these does not convert the nested part. As i understand is now array of ArrayLists. So is it possible to get an Array out of nested ArrayLists? 回答1: There is linear alternative for flatMap(): List<List

ArrayList : Find nth occurrence of an Integer

冷暖自知 提交于 2019-12-14 03:52:53
问题 What is the best way to find nth occurrence of a number in ArrayList? What I know already? To find lastIndexOf the number there is method in List interface, which is implemented in ArrayList class. To find first occurence there is indexOf method. What I was solving? In a problem there was a list with different numbers and I have to return index of two numbers whose sum is equal to target number. Ex: List = (1,2,1) & target = 2; Now 1 + 1 =2 and answer will be index of first 1 and second 1.

Type mismatch: cannot convert from Object to List

我的未来我决定 提交于 2019-12-14 03:52:52
问题 CompanyDAO companyDAO = new CompanyDAO(); List companyList = companyDAO.getAllCompanyList(); MycompanyList contains a data of like this : [[1, Agastha Medical Center], [2, Agastha Asthma]] Now i want to iterate the values and i want to pass a value of 1 to query but when i am placing this inside of a for loop i am getting for(int k=0;k<=companyList.size();k++){ List companyId =companyList.get(k); // [1, Agastha Medical Center] for k=0; Type mismatch: cannot convert from Object to List I need