array

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: find the only unpaired element in the array 7 answers The following is taken from a job interview: In a given array, which contains integers, each number repeats itself once except for one, which doesn't repeat. Write a function that finds the number that doesn't repeat. I thought about using an HashSet, but it might complicate everything... Any ideas of a simple solution? 回答1: You can define an integer "result" initialized to 0, and then you do some bitwise operations by applying a XOR logic to all

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: How do I create an array of strings in C? 14 answers I'm teaching myself C from a book and I am trying to create a crossword puzzle. I need to make an array of strings but keep running into problems. Also, I don't know much about array... This is the piece of the code: char word1 [6] ="fluffy", word2[5]="small",word3[5]="bunny"; char words_array[3]; /*This is my array*/ char *first_slot = &words_array[0]; /*I've made a pointer to the first slot of words*/ words_array[0]=word1; /*(line 20)Trying to

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Just need a hand understanding some simple database queries in ZF2. In ZF1 I have simple methods like this: public function recordset() { // listing of all records $db = Zend_Registry::get('db'); $sql = "SELECT " . $this->_selectlist() . " from customer c"; $r = $db->fetchAll($sql); return $r; } In ZF2, how would I do the same? I have tried the following, but this just returns what looks like a "Result" object, but all I want is an array like ZF1 did with fetchAll. If I have to iterate the result object only to provide the array later, which

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I am using the code below to trim some "blank cells" that contain a space. The thing is it takes too much time, as is looping to every cell. What I want is to remove the spaces(the ones in the beginning and end, not middle), of all the cells. Is there any easier way that I can apply all at once? For a = 1 To ScenarioTableLastRow For f = 1 To ScenarioTableLastColumn If Cells ( a , f ) <> "" Then Cells ( a , f ) = Excel . Application . Trim ( Cells ( a , f )) End If Next f Next a 回答1: You'll get much better performance copying the

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a set of greyscale images as a 2D numpy arrays. I need to rotate the images about one point (inside them) of different, float angles. The rotation doesn't need to be in place, and I will allow (of course, if I explained well so far) for interpolation. I'd like to remain in numpy, as I need to perform numerical operations on the result, but I can also (if that's impossible) allow for step in/out; for example I tried using PIL, namely Image.rotate(theta) but don't understand how to apply that to my arrays, and how to get an array back.

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I tried to use resize on an array in this way: a = np.array([1,2,3,4,5,6], dtype=np.uint8) a.resize(4,2) print a and the output is Ok!(I meant that there was no error). But when I run this code: a = np.array([1,2,3,4,5,6], dtype=np.uint8).reshape(2,3) a.resize(4,2) print a it gave rise to an error, saying that, ValueError: cannot resize this array: it does not own its data My question: why after applying reshape the ownership of array is changed? The ownership is granted to whom !? The reshape does not create a new memory and it is

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: So I know what the gradient of a (mathematical) function is, so I feel like I should know what numpy.gradient does. But I don't. The documentation is not really helpful either: Return the gradient of an N-dimensional array. What is the gradient of an array? When is numpy.gradient useful? 回答1: The gradient is computed using central differences in the interior and first differences at the boundaries. and The default distance is 1 This means that in the interior it is computed as where h = 1.0 and at the boundaries 回答2: Also in the

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Is there any cool way in Ruby to create an array with 1 to 100 with only odd entries (1, 3 etc). I now have a loop for this but that is obviously not a cool way to do it! Any suggestions? My current code: def create_1_to_100_odd_array array = [1] i = 3 while i < 100 array.push i i += 2 end array end Thanks in advance 回答1: The Range class comes with a very cool feature for that purpose: 1.9.3-p286 :005 > (1..10).step(2).to_a => [1, 3, 5, 7, 9] 回答2: May not be efficient, but a short piece of code: (1..100).select(&:odd?) # => [1, 3, 5, 7, 9,

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have the following view model: function instance(id, FirstName){ $.extend(this, { id: ko.observable(id || ''), FirstName: ko.observable(FirstName || '') }); } I have some instances in an observableArray: ko.observableArray([new instance(...), new instance(...), ...] With the following template: <ul data-bind='template: {name: "instanceTemplate", foreach: instances}'></ul> And another template: <ul data-bind='template: {name: "anotherInsTmpl", foreach: instances}'></ul> In first ul I need to render templates without sorting, in the second

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I learned from C Primer Plus that if you want to protect an array from being accidentally modified by a function, you should add const modifier before the pointer declaration in the header of function definition. Following this sensible advice, in the following minimal example, I'm trying to pass a non-constant two-dimensional array array to the function Sum2D , one parameter of which is a pointer-to-const-int[2] . #include #define ROWS 2 #define COLS 2 int Sum2D(const int ar[][COLS], int rows); //use `const` to protect input array int main