array

How to convert multi-dimensional array into single array using php?

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: After implementing database queries, I am getting the multi-dimensional array below. Two Dimensional Array Array ( [0] => Array ( [t1] => test1 ) [1] => Array ( [t2] => test2 ) [2] => Array ( [t3] => test3 ) [3] => Array ( [t4] => test4 ) [4] => Array ( [t5] => test5 ) ) but I want to convert it to a single dimensional array, like the format below. One Dimensional Array Array ( t1 => test1 t2 => test2 t3 => test3 t4 => test4 t5 => test5 ) Please help me to do so 回答1: I think you can use array_reduce() function. For example: $multi= array(0 =

Jax-rs(Jersey) to Consumes Array of Json object in POST request

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Using the jax-rs(Jersey) I am try to implement a POST request that take a list of JSON object //The resource look like this @Path("/path") @POST @Consumes(MediaType.APPLICATION_JSON) public void setJsonl(List<SomeObj> test) { //do work System.out.println(test); } //The class to define the json structure @XmlRootElement public class SomeObj{ private String tag; private String value; public String getTag() { return tag; } public void setTag(String tag) { this.tag = tag; } public String getValue() { return value; } public void setValue(String

PHP Mongo Query NOT NULL

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Anyone know the syntax for writing a php-mongo query to use NOT NULL ? I know how to do this when I query for NULL : <?php $cursor = $collection->find(array("someField" => null)); Is this even possible? 回答1: Yeah, you want the $ne operator, so $cursor = $collection->find(array("someField" => array('$ne' => null))); 回答2: Basically, the same kind of queries you would use on the Mongo console, you pass as an array to the query methods. In your case, it could be (if you're checking that the field exists - note that the field could just be absent

Passing a numpy pointer (dtype=np.bool) to C++

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'd like to use a numpy array of type bool in C++ by passing its pointer via Cython. I already know how to do it with other datatypes like uint8. Doing it the same way with boolean it does not work. I am able to compile but there is the following Exception during runtime: Traceback (most recent call last): File "test.py", line 15, in <module> c = r.count(b, 4) File "rect.pyx", line 41, in rect.PyRectangle.count (rect.cpp:1865) def count(self, np.ndarray[bool, ndim=1, mode="c"] array not None, int size): ValueError: Does not understand

Python/Scipy 2D Interpolation (Non-uniform Data)

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This is a follow-up question to my previous post: Python/Scipy Interpolation (map_coordinates) Let's say I want to interpolate over a 2d rectangular area. My variable 'z' contains the data as shown below. Each column is at a constant value, however, each row of the array may be at a different value as shown in the comment below. from scipy import interpolate from numpy import array import numpy as np # # 0.0000, 0.1750, 0. 8 170, 1.0000 z = array([[-2.2 8 1 8 ,-2.2 8 1 8 ,-0.9309,-0.9309], # 0.0000, 0.0000, 0.0000, 0.0000 [-2.2 8 1 8 ,-2.2 8

return group_concat data as array

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I want to return values I retrieve from the db using group_concat as an array of data. Is it possible to do this in the mysql query? Or do I need to explode the data into an array? GROUP_CONCAT(sh.hold_id) as holds returns this [holds] => 3,4 I want it to return: [holds] => array(3,4) 回答1: As I said in my comment: you need to explode the data into an array, using php code like this: $holds = explode(',', $holds); because mysql has no concept of array-type for data. 回答2: MySQL has no concept of arrays. Therefore it is not able to return an

Hide some maybe-no-member Pylint errors

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: The following Python fragment code gets analyzed by Pylint : if type(result) is array.array: read = result.tobytes() ... with the following error for the last line: E:401,22: Instance of 'int' has no 'tobytes' member\ (but some types could not be inferred) (maybe-no-member) The result variable is received from an external function. How can I change (correct) the code to make Pylint understand? Or how can I tell it that the result of the function can have other types than int? Or how can I tell it to ignore that particular line? (I favor an

What is the best way to convert a SymPy matrix to a numpy array/matrix

匿名 (未验证) 提交于 2019-12-03 08:35:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am not sure if the approach I've been using in sympy to convert a MutableDenseMatrix to a numpy.array or numpy.matrix is a good current practice. I have a symbolic matrix like: g = sympy.Matrix( [[ x, 2*x, 3*x, 4*x, 5*x, 6*x, 7*x, 8*x, 9*x, 10*x] [x**2, x**3, x**4, x**5, x**6, x**7, x**8, x**9, x**10, x**11]] ) and I am converting to a numpy.array doing: g_func = lambda val: numpy.array( g.subs( {x:val} ).tolist(), dtype=float ) where I get an array for a given value of x . Is there a better built-in solution in SymPy to do that? Thank you

numpy.array boolean to binary?

匿名 (未验证) 提交于 2019-12-03 08:35:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am trying to rewrite a matlab code in python27. There is a matlab line as follows: vector_C = vector_A > vector_B; If I try to write this in python using numpy it will be the same, but the result will be an array of booleans instead of binaries. I want the result to be in binaries. Is there a way to make it return binary or should I convert manually each time? Is there a quick way of converting it? I am new to python. Thanks. 回答1: Even though vector_C may have dtype=bool , you can still do operations such as the following: In [1]: vector_A

C - pointers and different results?

匿名 (未验证) 提交于 2019-12-03 08:35:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I cannot figure this out. Perhaps it is because it's 2am. At any rate, I am at a loss here. #include <stdio.h> int main () { char array [] = "123456789" ; char * ptr = array ; printf ( "%c\n" , *( ptr ++)); printf ( "%c\n" , * ptr ); * ptr = array [ 3 ]; printf ( "%c\n" , *( ptr ++)); printf ( "%c\n\n" , * ptr ); return 0 ; } The result is: 1 2 4 3 I have a pointer, which I assign to array . I then print, what I thought would be the first index ( '2' ), but instead get 1 . -- So, I assume that *(ptr++) actually dereferences, before