array-initialization

string[][] Tablero = new string[3][3]; I need to have a 3x3 array arrangement to save information to. How do I declare this in C#? explorer string[,] Tablero = new string[3,3]; You can also instantiate it in the same line with array initializer syntax as follows: string[,] Tablero = new string[3, 3] {{"a","b","c"}, {"d","e","f"}, {"g","h","i"} }; You probably want this: string[,] Tablero = new string[3,3]; This will create you a matrix-like array where all rows have the same length. The array in your sample is a so-called jagged array , i.e. an array of arrays where the elements can be of

I need to initialize each element of an array to a non-constant expression. Can I do that without having to first initialize each element of the array to some meaningless expression? Here's an example of what I'd like to be able to do: fn foo(xs: &[i32; 1000]) { let mut ys: [i32; 1000]; for (x, y) in xs.iter().zip(ys.iter_mut()) { *y = *x / 3; } // ... } This code gives the compile-time error: error[E0381]: borrow of possibly uninitialized variable: `ys` --> src/lib.rs:4:33 | 4 | for (x, y) in xs.iter().zip(ys.iter_mut()) { | ^^ use of possibly uninitialized `ys` To fix the problem, I need to

By accident I found that the line char s[] = {"Hello World"}; is properly compiled and seems to be treated the same as char s[] = "Hello World"; . Isn't the first ( {"Hello World"} ) an array containing one element that is an array of char, so the declaration for s should read char *s[] ? In fact if I change it to char *s[] = {"Hello World"}; the compiler accepts it as well, as expected. Searching for an answer, the only place I found which mentioned this is this one but there is no citing of the standard. So my question is, why the line char s[] = {"Hello World"}; is compiled although the

Hello I am a beginner in C programming language , recently i started learning arrays , I have studied that by default all values in an int array are garbage . Then why i am getting different values in these two cases. Case-1 int arr[5]; in this case from arr[0] till arr[4] we will have garbage values, but in next case. Case-2 int arr[5] = {1}; in this case arr[0] will have a value 1 and remaining from arr[1] to arr[4] will have value 0. My question is that, When in case-1 each un-initilized array locations are having garbage valeus then why in case-2 remaining un-initilized array locations are

I've got a method that receives a variable int. That variable constitutes an array size (please, don't offer me a vector). Thus, I need to init a const int inside my method to initialize an array of specific size. Question: how do I do that? void foo(int variable_int){ int a[variable_int] = {0}; //error } int *a = new int[variable_int]; Remember to delete[] the allocated space when you are done with it! You asked for a non-vector solution but let's go over it because you might have rejected it for the wrong reasons. You shouldn't worry about performance because at the hands of any competent