arithmeticexception

Not a Number (NaN)

由 有些话、适合烂在心里 提交于 2020-04-30 08:02:18
问题 Why some numbers are defined as not a number(NaN) in floating point arithmetic? (Although they can be represented by IEEE format and indeed are real numbers) 回答1: The author of the question also posted this comment: I don't understand how numbers for which "all exponent bits are 1's and mantissa is not all zeros" is not a real number. The reasoning behind this comment appears to be: A binary floating-point format has a sign bit s , some exponent bits e , and some significand bits f . For most

Not a Number (NaN)

由 本秂侑毒 提交于 2020-04-30 08:01:50
问题 Why some numbers are defined as not a number(NaN) in floating point arithmetic? (Although they can be represented by IEEE format and indeed are real numbers) 回答1: The author of the question also posted this comment: I don't understand how numbers for which "all exponent bits are 1's and mantissa is not all zeros" is not a real number. The reasoning behind this comment appears to be: A binary floating-point format has a sign bit s , some exponent bits e , and some significand bits f . For most

Not a Number (NaN)

由 牧云@^-^@ 提交于 2020-04-30 08:01:05
问题 Why some numbers are defined as not a number(NaN) in floating point arithmetic? (Although they can be represented by IEEE format and indeed are real numbers) 回答1: The author of the question also posted this comment: I don't understand how numbers for which "all exponent bits are 1's and mantissa is not all zeros" is not a real number. The reasoning behind this comment appears to be: A binary floating-point format has a sign bit s , some exponent bits e , and some significand bits f . For most

Dividing a double by zero in Java [duplicate]

由 梦想的初衷 提交于 2019-12-24 04:51:48
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Why doesn't Java throw an Exception when dividing by 0.0? Why the following statement in Java will not report an ArithmeticException? double d = 1.0/0; 回答1: In short: floating point numbers can represent infinity (or even operations that yield values which aren't numbers) so an operation that results in this (e.g. dividing by 0) is valid. Expanding upon Mohammod Hossain's answer, as well as this question and its

Points calculated using this elliptic curve point multiplication do not lie on the curve and this class brings Arithmetic exception

由 余生颓废 提交于 2019-12-21 03:18:07
问题 I get stack on my error of point multiplication using standard projective coordinates. I don't know what i missed but the multiplied points do not lie on the curve and some times it outputs something like Arithmetic Exception: integer is not invertible. public class ECPointArthimetic { EllipticCurve ec; private BigInteger x; private BigInteger y; private BigInteger z; private BigInteger zinv; private BigInteger one = BigInteger.ONE; private BigInteger zero = BigInteger.ZERO; private boolean

How to prevent arithmetic overflow error when using SUM on INT column?

由 倖福魔咒の 提交于 2019-12-18 12:09:25
问题 I am using SQL Server 2008 R2 and I have an INT column where the data inserted never surpasses the max INT , but I have a query which uses the SUM function which when executed surpasses the max INT limit and throws the error mentioned in the title. I want to be able to execute this query without changing the column type from INT to BIGINT . Here is my query: SELECT UserId, SUM( PokemonExp ) AS TotalExp, MAX( PokemonLevel ) AS MaxPokeLevel FROM mytable GROUP BY UserId ORDER BY TotalExp DESC

BigDecimal Underflow

由 試著忘記壹切 提交于 2019-12-06 10:11:37
问题 I am trying to render a fractal called the "Lorenz Attractor" with Java. Because double does not work (values out of range), I decided to choose BigDecimals. After 38 iterations my code crashes, it gets me an ArithmeticException (Underflow). Heres some of the code: BigDecimal xnew = this.x.add(this.hBig.multiply(BigDecimal.TEN).multiply(this.x.add(this.y.negate()))); //This is the line that crashes BigDecimal ynew = this.y.add(this.hBig.multiply(this.x.negate().multiply(this.z)).add

BigDecimal Underflow

由 拟墨画扇 提交于 2019-12-04 14:59:33
I am trying to render a fractal called the "Lorenz Attractor" with Java. Because double does not work (values out of range), I decided to choose BigDecimals. After 38 iterations my code crashes, it gets me an ArithmeticException (Underflow). Heres some of the code: BigDecimal xnew = this.x.add(this.hBig.multiply(BigDecimal.TEN).multiply(this.x.add(this.y.negate()))); //This is the line that crashes BigDecimal ynew = this.y.add(this.hBig.multiply(this.x.negate().multiply(this.z)).add(ZWENTYEIGHT.multiply(this.x.add(this.y.negate())))); BigDecimal znew = this.z.add(this.hBig.multiply(this.x

Project Euler #3 out of integer range java [duplicate]

由 ﹥＞﹥吖頭↗ 提交于 2019-12-04 06:04:12
问题 This question already has answers here : The literal xyz of type int is out of range (5 answers) Closed 4 years ago . The code is supposed to give back the biggest prime number. More about the task here: https://projecteuler.net/problem=3 int checkFactors(double na) { long n = (long) na; int biggestPrimeFactor = 0; for (int i = 1; i < n; i++) if (n % i == 0 && isPrimFaktor(i) && i > biggestPrimeFactor) biggestPrimeFactor = i; return biggestPrimeFactor; } boolean isPrimeFactor(int n) { int

ASP.NET Overflow or underflow in the arithmetic operation when returning large file bigger 1 GB

由 一个人想着一个人 提交于 2019-12-03 16:06:42
问题 I went across some sort of limitation in ASP.NET. I reduced the problem into a sample project in ASP.NET MVC Project (created with Visual Studio 2010 and .NET 4) and the problem still occurs: In a MVC Controller I have a method which provides a file download: public ActionResult DownloadBigFile() { string file = @"C:\Temp\File.txt"; var readStream = new FileStream(file, FileMode.Open, FileAccess.Read); return File(readStream, "text/plain", "FILE"); } When the file is below 1 GB the download
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