args

问题 When I pass in "$1000" through the command line and retrieve the string through args[0], it becomes "000". How can I maintain the full string in my java code? 回答1: I guess you're using some kind of Unix system, as '$' is the variable symbol in bash & co. Try using single quotes (e.g. java MyClass '$1000' ) 来源： https://stackoverflow.com/questions/33353649/escape-dollar-sign-in-command-line-arguments

问题 I've got the following and was wondering if the initial test is overkill: static void Main(string[] args) { if (args.Length == 0 || args == null) { //do X } else { //do Y } } in other words what I'm asking is are there possibilities of args.Length being zero, or args being null....or would just one of these conditions sufficed? 回答1: Well, Main is defined to never ever ever ever be called with a null parameter. If it does somehow receive a null parameter, then your environment is so broken

问题 The header for the main method is public static void main (String[] args) Could you technically replace "args" with anything you want? Also, why is the parameter an array? 回答1: args is just a name for the argument in a method. You can rename it to whatever you want. The JVM doesn't need to know what the argument is named ; only the type , String[] , is important. dont break the start point of the app static void main(String[] whateverYouNeed) 回答2: You can rename it to any proper Java

问题 I just have a small question which i cant understand , i hope i can get some help please . I Want to write a program that get the info into my program using the command line, example (java xx 10 20). In my program i got something like this int coffeeCups= Integer.parseInt(args[0]); int coffeeShots= Integer.parseInt(args[1]); if (args.length==0) { System.out.print ("No arguments.."); System.exit(0); } else if (args.length==1) {System.out.println("not enough arg.."); System.exit(0); } else if

问题 I'm making a function that takes a variable number of lists as input (i.e., an arbitrary argument list). I need to compare each element from each list to each element of all other lists, but I couldn't find any way to approach this. 回答1: The itertools module provides a lot of useful tools just for such tasks. You can adapt the following example to your task by integrating it into your specific comparison logic. Note that the following assumes a commutative function. That is, about half of the

问题 I have a class that gets initialized with a previously unknown number of arguments and I want it to be done on cli using python click package. My issue is that I can't manage to initialize it and run a click command: $ python mycode.py arg1 arg2 ... argN click_command because with variadic arguments option nargs=-1 click don't recognize the click_command as a command. How can I input N args and then run a command using click? Setting a defined number of arguments, like nargs=5 , solves the

问题 I would like to write a Python script that takes some necessary positional and some optional command-line arguments via argparse : Let's call the positional args a , b , c , and the optional arguments x , y , z . In my Python script, I would like to pass these args on to a function; specifically, I want a , b , c to be passed as *args , and x , y , z to be passed as **kwargs , the latter retaining their names. I would like to do this many times with different functions and different numbers

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago . I would like to my function func(*args, **kwargs) return one dictionary which contains all arguments I gave to it. For example: func(arg1, arg2, arg3=value3, arg4=value4) should return one dictionary like this: {'arg1': value1, 'arg2': value2, 'arg3': value3, 'arg4': value4 } 回答1: You can use

问题 following this topic: allow users to "extend" API functions class Inspector: def __init__(self, passedFunc): self.passedFunc = passedFunc def __call__(self, *args, **kwargs): # Inspector needs to generate a list of arguments of the passed function and print them in *correct* order # now how to generate a list of arguments using data from both ''args' and 'kwargs'? # the user might keep default argument values, in which case both will be None, # he might only use args, in which case it is easy

问题 What is the use of * in .format(*) ? When using it in the format function below print(new_string.format(*sum_string)) it changes the value of sum_string in the output from 18 to 1 Why does that happen? I have read the following link about *args and **kwargs but couldn't understand how does that apply to the .format() function What does ** (double star/asterisk) and * (star/asterisk) do for parameters? sum_string = "18" new_string = "This is a new string of value {}" print(new_string.format