alias

问题 I am quite confused in implementing namespace in php, especially when it comes to alias - importing classes. I have followed the tutorial from this tutorial: Leveraging PHP V5.3 namespaces for readable and maintainable code (by Don Denoncourt; 1 Mar 2011; for IBM Developerworks) But I don't understand - when __autoload is used, why I have to store the alias classes in folders, but when __autoload is not used, the alias in namespace are just fine, like this below, <?php namespace barbarian;

问题 I have tried some ways to create an alias for my local Drupal project, I'm referring to : https://www.drupal.org/node/1401522 https://www.drupal.org/project/drush/issues/831272 https://www.drupal.org/project/drush/issues/786766 I can connect by running this command : drush --root=C:/wamp64/www/executive-coatings --uri=http://localhost:81/executive-coatings status Output : Drupal version : 8.6.13 Site URI : http://localhost:81/executive-coatings DB driver : mysql DB hostname : localhost DB

问题 How can I use my column alias (lat and lng) from the two subqueries to make the distance calcuation underneath? What I am basically trying to do is is to calculate the distance between two locations using longitude and latitude values. But somehow my aliases aren't usable in the query, why? SELECT wp_posts.*, (SELECT wp_postmeta.meta_value FROM wp_postmeta WHERE wp_postmeta.post_id = wp_posts.ID AND wp_postmeta.meta_value LIKE '41.%') AS lat, (SELECT wp_postmeta.meta_value FROM wp_postmeta

问题 This question already has answers here : Creating permanent executable aliases (4 answers) Closed 5 years ago . If you create an alias for example: alias cls="clear" It exists untill you kill terminall session. When you start a new terminal window the alias doesn't exist any more. How to create "permanent" alias, one that exists in every terminal session? 回答1: You can put such aliases in the ~/.bash_aliases file. That file is loaded by ~/.bashrc. On Ubuntu 10.04, the following lines need to

问题 Is there a way to list all aliases, something like: $ ls-aliases .. "cd .." la "ls -Gla" gs "git stash" etc... Also is it possible to add human readable descriptions to aliases ? I'm on a MacOSX 回答1: In bash : To list all aliases: alias To add a comment, just put it at the end of the command, e.g.: $ alias foo='echo bar #some description' $ foo bar $ alias foo alias foo='echo bar #some description' 回答2: Note that in fish the alias command creates a function using the alias name that wraps the

问题 I need to use result of a SQL query to set column aliases. Please see below script and the result of the script I need to use it as column aliases. select convert(varchar,DATEADD(month, -12, dateadd(d,-day(convert(date,dateadd(d,-(day(getdate())),getdate()))),convert(date,dateadd(d,+1-(day(getdate())),getdate())))),107), convert(varchar,convert(date,dateadd(d,-day(convert(date,dateadd(d,-(day(getdate())),getdate()))),convert(date,dateadd(d,+1-(day(getdate())),getdate())))),107) I need the

问题 I'm a graphic designer trying my best to understand table aliases, but it's not working. Here's what I have so far: SELECT colours.colourid AS colourid1, combinations.manufacturercolourid AS colourmanid1, colours.colourname AS colourname1, colours.colourhex AS colourhex1, combinations.qecolourid2 AS colouridqe2, colours.colourid AS colourid2, colours.colourname AS colourname2, colours.colourhex AS colourhex2, colours.colourid AS colourid3, combinations.qecolourid3 AS colouridqe3, colours

问题 Most SQL experts would say one can't re-use an alias in a select at the same level; often to work around this a CTE is used; or one wraps the query as a subquery so the alias can be referenced. However, mySQL seems to allow such a situation provided the alias is referenced in a subquery within the select itself; so it's not technically at the same level. DEMO: SELECT CONCAT(a, b) AS c1, CONCAT((SELECT c1), 2) FROM (SELECT 'a' a, 'b' b, 'c' c UNION ALL SELECT '1', '2', '3') t1; SELECT 1 a, 2 b

问题 The following code is from http://www.pvv.org/~oma/PubQuiz_ACCU_Apr2014.pdf (#6, solution on page 34). The goal was to guess the output for the following. #include <iostream> template <template <typename> class> struct X { X() { std::cout << "1"; } }; template<typename > struct Y {}; template<typename T> using Z = Y<T>; template<> struct X<Y> { X() { std::cout << "2"; } }; int main() { X<Y> x1; X<Z> x2; } The answer can be found on page 34. I don’t understand the second case with the alias

问题 I want to (am trying to) make my code more readable. I have been using the following class aliasing. using Histogram = EmpiricScore<int>; using FeatureHistogram = Dictionary<string, EmpiricScore<int>>; But I think something like (note: I'm attempting to describe FeatureHistogram in terms of Histogram here, rather than EmpiricScore<int>> ): using Histogram = EmpiricScore<int>; using FeatureHistogram = Dictionary<string, Histogram>; Seems more readable (the dependencies can go much deeper, what