alarm

I'm trying to build a python timeout exception that runs in milliseconds. The python signal.alarm function has a 1 second resolution. How would one get an equivalent function that requests a SIGALRM signal to a given process in, say milliseconds, as opposed to seconds? I've found no simple solutions as of yet. Thanks in advance for your input. Use signal.setitimer() instead. 来源： https://stackoverflow.com/questions/3770711/signal-alarm-function-with-resolution-greater-than-1-second

Even when my iPhone application is in background, How can I use UILocalNotification to show my alram every day at 8.00 PM? Set the fireDate to 8.00 PM and set the repeatInterval to NSDayCalendarUnit and schedule the alert with [[UIApplication sharedApplication] scheduleLocalNotification: myNotification]; dasdom answer is correct. just wanted to add to it that the alarm will not make a sound if your device is in silent mode. It is a restriction from Apple for UILocalNotification. UILocalNotification *localNotification =[[UILocalNotification alloc]init]; NSCalendar *calendar=[NSCalendar

I have the code : public void AlarmStart() { Calendar cal = Calendar.getInstance(); cal.add(Calendar.MINUTE, 5); Intent intent = new Intent(MainNote.this, AlarmReceiver.class); intent.putExtra("alarm_message", "MESS"); PendingIntent sender = PendingIntent.getBroadcast(MainNote.this, 1, intent, PendingIntent.FLAG_UPDATE_CURRENT); AlarmManager am = (AlarmManager) getSystemService(ALARM_SERVICE); am.set(AlarmManager.RTC_WAKEUP, cal.getTimeInMillis(), sender); } It calls AlarmReceiver class on time. public class AlarmReceiver extends BroadcastReceiver { @Override public void onReceive(Context

I have to crate a sample app in which when I clicked a button that should open the native alarm clock so that user can use it for setting alarm? Noah Witherspoon If the Clock app supported a URL scheme, like the Phone app’s tel:// or the Mail app’s mail:// , you could open it with the standard [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"..."]] approach. Unfortunately, to my knowledge, it doesn’t, so all you can really do is prompt the user to open that app themselves to set up the alarm. Alternatively, you can have your app set up a local notification to act as an alarm

I have an app running on Android that creates an alarm that is fired every 24 hours. This alarm is working as expected. However, when I update my app through Google Play this alarm is lost because the end user does not open the app right after the app was updated. My opinion is that Android is deleting the alarms my app created when the app was updated. Does anyone already got this situation? Is there any way to persist the alarms when the app is updated? Your solution is as simple as below: Have a broadcast receiver registered within your app with 2 intent filters namely: "android.intent

Hi I am trying to set Alarm in my application Using the AlarmClock class. I am using the code as follows: Intent intent = new Intent(); intent.setAction(AlarmClock.ACTION_SET_ALARM); startActivity(intent); But I am getting an exception. Can anyone please tell how to use this new Android feature? You'll also need to add <uses-permission android:name="com.android.alarm.permission.SET_ALARM"/> to your manifest. Ollie is right, the code should look something like the following: Intent i = new Intent(AlarmClock.ACTION_SET_ALARM); i.putExtra(AlarmClock.EXTRA_HOUR, 9); i.putExtra(AlarmClock.EXTRA