ajax

Reverse or hide jQuery ajax for input checkbox results

假装没事ソ 提交于 2020-12-13 04:05:33
问题 I don't have good knowledge about jquery, so I have a code working good but their problem, is to hide the result when uncheck the checkbox .( check to get the results from the database - uncheck hide these results ) catfd.php code <input type="checkbox" value="2" class="catcf"> catfd2 <br /> <input type="checkbox" value="35" class="catcf"> catfd35 <br /> <input type="checkbox" value="22" class="catcf"> catfd22 <br /> <input type="checkbox" value="133" class="catcf"> catfd133 <br /> <input

Reverse or hide jQuery ajax for input checkbox results

假如想象 提交于 2020-12-13 04:03:02
问题 I don't have good knowledge about jquery, so I have a code working good but their problem, is to hide the result when uncheck the checkbox .( check to get the results from the database - uncheck hide these results ) catfd.php code <input type="checkbox" value="2" class="catcf"> catfd2 <br /> <input type="checkbox" value="35" class="catcf"> catfd35 <br /> <input type="checkbox" value="22" class="catcf"> catfd22 <br /> <input type="checkbox" value="133" class="catcf"> catfd133 <br /> <input

Get elements with active class and send them in Ajax with jQuery

▼魔方 西西 提交于 2020-12-13 03:09:48
问题 If I have this HTML: <form> <a href="#" data-name="color" data-value="yellow" class="active"> <a href="#" data-name="color" data-value="red"> <a href="#" data-name="color" data-value="orange"> <a href="#" data-name="fruit" data-value="banana" class="active"> <a href="#" data-name="fruit" data-value="apple"> <buton id="send">Send</button> </form> How can I create an array with all the <a class="active"> through Ajax to play with them in PHP after ? Thanks. 回答1: You need to use formData to send

Get elements with active class and send them in Ajax with jQuery

南楼画角 提交于 2020-12-13 03:07:45
问题 If I have this HTML: <form> <a href="#" data-name="color" data-value="yellow" class="active"> <a href="#" data-name="color" data-value="red"> <a href="#" data-name="color" data-value="orange"> <a href="#" data-name="fruit" data-value="banana" class="active"> <a href="#" data-name="fruit" data-value="apple"> <buton id="send">Send</button> </form> How can I create an array with all the <a class="active"> through Ajax to play with them in PHP after ? Thanks. 回答1: You need to use formData to send

onchange get current value with radioChoice

南笙酒味 提交于 2020-12-11 01:40:11
问题 Im trying to get the selected value from a radio form with radioChoice onChange but can't really seem to find the solution. The onEvent function gets called, but from here I'm not really sure how to get the value. Code: RadioChoice<String> radioChoice = new RadioChoice<String>("radio", new PropertyModel<String>(this, "selected"),this.radioChoiceList); radioChoice.add(new AjaxFormComponentUpdatingBehavior("change") { @Override protected void onUpdate(AjaxRequestTarget target) { System.out

Datatables server-side processing in ASP.NET Core 3.1

醉酒当歌 提交于 2020-12-08 05:01:11
问题 I am new to Datatables with AJAX calls. I need to implement server-side processing for thousands of records. I was following a tutorial but I got confused somewhere with server side processing. I am getting an error while trying to render the data from the data source. Let me post all the relevant code and hope that you help me identify where I am getting it wrong. Since I am new to Datatables and Ajax, I will appreciate more answers with examples, textual answers accompanied by code or link

How to implement Pagination with dynamic HTML table data via AJAX?

陌路散爱 提交于 2020-12-08 04:39:29
问题 I want to display incoming data from my database to a dynamic HTML table (via AJAX) that should include pagination . I have read about DataTables pagination but I am not sure how to implement it here. This is the code: JS code: $.ajax({ cache: false, url: {% url 'grab_records' %}, method: 'GET', datatype: 'json', success: function(data) { var htmlData = ''; var res = data[0]; if (res) { var count = res.data.length; for (i = 0; i < count; i++) { htmlData += '<tr>' +'<td id = "records"> '+res

Append function() is not working in jQuery Ajax of PHP response

浪尽此生 提交于 2020-12-07 06:34:22
问题 I am getting the array through PHP and I want to append in in table but I tried to make it from last 2 days and uses all the function which available on stackoverflow but it not working... Please developers , help me and teach me how i append out output data in table as below - PHP Code :- $result = $stmt->fetchAll(); foreach($result as $data => $value) { //$QL QUERY HERE $data = array('name' => $value["name"], 'amount' => $amount, 'invoice' => $Invoice, 'response' => '200'); echo json_encode

Why the form is not JSON serializable?

痞子三分冷 提交于 2020-12-07 06:21:26
问题 I am using Django and I am trying when a button is clicked to get data from the database and fill a form with them through AJAX. I get the error TypeError: Object of type 'EditProductForm' is not JSON serializable from the edit_product_view in my views.py Below is the code I am working with: -urls.py from django.conf.urls import url from . import views app_name = "products" urlpatterns = [url(r'^products', views.ProductsView.as_view(), name="products"), url(r"^product/new", views.add_new

Why the form is not JSON serializable?

久未见 提交于 2020-12-07 06:20:53
问题 I am using Django and I am trying when a button is clicked to get data from the database and fill a form with them through AJAX. I get the error TypeError: Object of type 'EditProductForm' is not JSON serializable from the edit_product_view in my views.py Below is the code I am working with: -urls.py from django.conf.urls import url from . import views app_name = "products" urlpatterns = [url(r'^products', views.ProductsView.as_view(), name="products"), url(r"^product/new", views.add_new