aes

String plain1= "Test"; byte[] cipher = SplashSecure.getInstance().encrypt2(plain1); String plain2 = SplashSecure.getInstance().decrypt2(cipher); plain = Test������������������������ After decryption plainText2 should be equal to plaintext . But it's not. Encrypt/Decrypt methods. public void initKey(String key) { String paddedKey = Utils.padString(key); mKeyspec = new SecretKeySpec(Utils.getBytes(paddedKey), "AES/ECB/NoPadding"); // Utils.getBytes returns "paddedKey.getBytes("CP1252")" } public byte[] encrypt2(String data) { try { Cipher cipher = Cipher.getInstance("AES/ECB/NoPadding"); cipher

I have two applications that interact using Thrift. They share the same secret key and I need to encrypt their messages. It makes sense to use symmetric algorithm (AES, for example), but I haven't found any library to do this. So I made a research and see following options: Use built-in SSL support I can use built-in SSL support, establish secure connection and use my secret key just as authentication token. It requires to install certificates in addition to the secret key they already have, but I don't need to implement anything except checking that secret key received from client is the same

This question already has answers here : Closed 2 years ago . InvalidKeyException Illegal key size (5 answers) I'm trying to decrypt with AES some data. I've been given a 256 bit key and 16 byte IV like these: String key = "Hh1s1f4T2mpN3yCh4ngeL8t3r\\.Thxpp"; int[] v = {11, 1, 555, 222, 241, 21, 11, 33, 35, 91, 45, 6, 14, 30, 22, 234}; String IV = Arrays.toString( v ); I've been told the padding should be PKCS7 but when I init the cipher with AES/CBC/PKCS7PADDING it says: Cannot find any provider supporting AES/CBC/PKCS7PADDING If I use AES/CBC/PKCS5PADDING I get Illegal key size but I've

I was looking for a way to encrypt a string in Java, and decrypt it in PHP. I found this in an answer somewhere on Stackoverflow and I modified it to do the exact opposite. This is my code to encrypt in Java: public static String encrypt(String data, String initialVectorString, String secretKey) { String encryptedData = null; try { SecretKeySpec skeySpec = new SecretKeySpec(md5(secretKey).substring(0, 16).getBytes(), "AES"); IvParameterSpec initialVector = new IvParameterSpec(initialVectorString.getBytes()); Cipher cipher = Cipher.getInstance("AES/CFB8/NoPadding"); cipher.init(Cipher.ENCRYPT

There is a very good example for random access AES CTR mode and it works: Random access InputStream using AES CTR mode in android private static final int AES_BLOCK_SIZE = 16; private static IvParameterSpec calculateIVForOffset(final IvParameterSpec iv, final long blockOffset) { final BigInteger ivBI = new BigInteger(1, iv.getIV()); final BigInteger ivForOffsetBI = ivBI.add(BigInteger.valueOf(blockOffset / AES_BLOCK_SIZE)); final byte[] ivForOffsetBA = ivForOffsetBI.toByteArray(); final IvParameterSpec ivForOffset; if (ivForOffsetBA.length >= AES_BLOCK_SIZE) { ivForOffset = new IvParameterSpec

note: Java NOOB. Alright, I know this has been answered a few dozen times on here, but the solutions don't seem to work/apply directly to where I understand them. (Yes, I know I don't completely understand encryption/decryption, AES, etc. but that is not the point, I am trying to understand this) I have a utility api where I want to pass a string and return an encrypted string. Then I want to pass the encrypted string, and return a decrypted string. Simple. It works fine for many strings I pass in, but on some, I'm getting the exception javax.crypto.BadPaddingException: Given final block not

CMDB和自动化运维 IT运维的分类 IT运维，指的是对已经搭建好的网络，软件，硬件进行维护。运维领域也是细分的，有硬件运维和软件运维 硬件运维主要包括对基础设施的运维，比如机房的设备，主机的硬盘，内存这些物理设备的维护 软件运维主要包括系统运维和应用运维，系统运维主要包括对OS，数据库，中间件的监控和维护，这些系统介于设备和应用之间，应用运维主要是对线上业务系统的运维 这里讨论的主要是软件运维的自动化，包括系统运维和应用运维的自动化 传统运维痛点 日常工作繁琐 日常运维工作是比较繁琐的，研发同学会经常需要到服务器上查日志，重启应用，或者是说今天上线某个产品，需要部署下环境。这些琐事是传统运维的大部分工作 应用运行环境不统一 在部署某应用后，应用不能访问，就会听到开发人员说，在我的环境运行很好的，怎么部署到测试环境后，就不能用了，因为各类环境的类库不统一 还有一种极端情况，运维人员习惯不同，可能凭自己的习惯来安装部署软件，每种服务器上运行软件的目录不统一 运维及部署效率低下 想想运维人员需要登陆到服务器上执行命令，部署程序，不仅效率很低，并且非常容易出现人为的错误，一旦手工出错，追溯问题将会非常不容易 无用报警信息过多 经常会收到很多报警信息，多数是无用的报警信息，造成运维人员经常屏蔽报警信 另外如果应用的访问速度出了问题，总是需要从系统、网络、应用、数据库等一步步的查找原因

import javax.crypto.Cipher; public abstract class Crypto { private static final String CIPHER_ALGORITHM = "AES/CTR/NoPadding"; private String AesKeyString = "ByWelFHCgFqivFZrWs89LQ=="; private void setKey() throws NoSuchAlgorithmException{ byte[] keyBytes; keyBytes = Base64.getDecoder().decode(AesKeyString); aesKey = new SecretKeySpec(keyBytes, "AES"); } protected byte[] execute(int mode, byte[] target, byte[] iv) throws Exception{ Cipher cipher = Cipher.getInstance(CIPHER_ALGORITHM); IvParameterSpec ivSpec = new IvParameterSpec(iv); cipher.init(mode, aesKey, ivSpec); return cipher.doFinal

Here's a sample dummy code called test(), I run this 100K times and I get different encrypted messages for the same plain text (obviously, the decryption I get is the original plain text). I guess the reason behind this is to avoid frequency; but how come there can be MANY encryption to ONE decryption? shouldn't it be a one to one? public static void test() { String plainMessage = "I'm gonna bid 100 USD on this project"; String password = "A99922000001000004581F0F0CCD0000"; Set<String> set = new HashSet<String>(); for (int x=0; x<100000; x++) { String enc = AESEncryption.encryptMessage