aes

I am using a AES cipher with a 16 byte block size. If I try and encrypt a 16 byte string I have no problems, but any other length not a multiple of 16 is throwing an exception. I know with 3-DES you can specify a padding type as part of the algorithm and it's handled with no extra work (e.g. DES/CBC/PKCS5Padding), but is there a way to specify this with AES? Or do I need to pad the pytes manually to a multiple of 16, and then strip them when I decrypt? Here is an abbreviated code sample. encrypt = Cipher.getInstance("AES", provider); encrypt.init(Cipher.ENCRYPT_MODE, key) ; byte[] encrypted =

实际测试 KEY 是 16个 byte，byte[] byteKEY = System.Convert.FromBase64String(key); 注意：是Convert.FromBase64String转 byte[] , 而不是 Encoding.UTF8.GetBytes 转 byte[] 。 IV 也是 16个 byte，全是0； -- /// <summary> /// 支付宝小程序AES密钥解密 /// </summary> /// <param name="decryptStr"></param> /// <param name="key">小程序后台设置里的AES密钥</param> /// <returns></returns> public static string AliPayLittleAppAesDecrypt(string decryptStr, string key) { //IV 16 个 byte 都是 0 int ivSize = 16; byte[] iv = new byte[ivSize]; for (int i = 0; i < ivSize; ++i) { iv[i] = 0; } //https://docs.open.alipay.com/common/104567 //支付宝小程序的AES密钥串是BASE64编码过的

I have looked a bit into cryptography and related matters during the last couple of days and am pretty confused by now. I have a question about password strength and am hoping that someone can clear up my confusion by sharing how they think through the following questions. I am becoming obsessed about these things, but need to spend my time otherwise :-) Let's assume we have an eight-digit password that consists of upper and lower-case alphabetic characters, numbers and common symbols. This means we have 96^8 ~= 7.2 quadrillion different possible passwords. As I understand there are at least