aes

How do i decrypt a file in Android with AES?

做~自己de王妃 提交于 2019-11-29 04:17:31
问题 I have a file (mp3) that i Encrypt, my intention is then to download this file to an android device and decrypt it, but during decryption i get an IOException: java.io.IOException: last block incomplete in decryption I am aware of the obvious security flaws in the following code, I'm just trying to get it to work first. Any help on this is appreciated and I am quite a newcomer to coding in general so excuse me in advance if this is a stupid question! Encryption class(Not done in Android,

incorrect decryption using AES/CBC/PKCS5Padding in Android

白昼怎懂夜的黑 提交于 2019-11-29 03:57:30
问题 I wrote the following code in Android (v2.2 API 8), where a plain text is entered and the code encrypts it using a user password and a random salt and then decrypts it. After running the code I only get part of the plain text correct. For example the user enters "Msg 1.5 to encrypt" and the result from the decryption code is "Msg15toencrypg==" Here is the code: private EditText plain_msg; private EditText pwd; private TextView result; byte[] iv; @Override public void onCreate(Bundle

Source and importance of nonce / IV for protocol using AES-GCM

你离开我真会死。 提交于 2019-11-29 03:45:57
I am making a protocol that uses packets (i.e., not a stream) encrypted with AES. I've decided on using GCM (based off CTR) because it provides integrated authentication and is part of the NSA's Suite B. The AES keys are negotiated using ECDH, where the public keys are signed by trusted contacts as a part of a web-of-trust using something like ECDSA. I believe that I need a 128-bit nonce / initialization vector for GCM because even though I'm using a 256 bit key for AES, it's always a 128 bit block cipher (right?) I'll be using a 96 bit IV after reading the BC code. I'm definitely not

RijndaelManaged “Padding is invalid and cannot be removed” that only occurs when decrypting in production

霸气de小男生 提交于 2019-11-29 03:32:23
I know other questions have been asked on this but none so far have provided a solution or are exactly the issue I have. The class below handles the encryption and decryption of strings, the key and vector passed in are ALWAYS the same. The strings being encrypted and decrypted are always numbers, most work but the occasional one fails when decrypting (but only on the production server). I should mention that both local and production environments are in IIS6 on Windows Server 2003, the code that uses the class sits in a .ashx handler. The example that fails on the production server is

not decrypting what I crypted

走远了吗. 提交于 2019-11-29 02:46:16
I have a weird problem... Basing my solution on Decrypting a hardcoded file as byte[] So, I wrote a small Cypher class to help out with crypting/decrypting... It used to mock-up a key hardcoded at some place and another pre-crypted key stored somewhere else. But that's somewhat irrelevant atm. the crypting process went like this: retrieve the hardcoded byte array use it to decrypt key2 use key2 to decrypt data use key1 to further decrypt data have decrypted data I was storing the crypted data as a hex-string, used these two functions to get in-out of there private static String

Implement OpenSSL AES Encryption in Python

霸气de小男生 提交于 2019-11-29 02:45:06
I'm trying to implement the following in Python: openssl enc -e -aes-256-cbc -base64 -k "Secret Passphrase" -in plaintext.txt -out ciphertext.txt openssl enc -d -aes-256-cbc -base64 -k "Secret Passphrase" -in ciphertext.txt -out verification.txt I've tried several different modules, PyCrypto, M2Crypto, etc but can't seem to get the correct combination of changing the password to the right size key and encoding everything correctly. I've found https://github.com/nvie/SimpleAES but that basically runs OpenSSL on the command line, which I'd rather avoid. SquareRootOfTwentyThree Base 64 encoding

How does Mega's encryption work for sharing?

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-29 01:11:01
问题 I have some issues regarding to find a way to achieve the encryption of arbitrary data that can be shared with multiple recipients. Mega seems to do exactly that. As far as I read it encrypts the data before its uploaded to the web server. Still it is possible to share that file with others. How is that done with the encryption? Imagine the following scenario: User Alice uploads a file to the server, it is being encrypted Alice wants to share that file with Bob and Dave. How can Bob and Dave

last block incomplete with CipherInputStream/CipherOutputStream, even with padding AES/CBC/PKCS5Padding

和自甴很熟 提交于 2019-11-29 01:07:21
问题 Actually, I searched lot from internet and in stackoverflow too for this, Initially I don't used padding in my encryption and decryption, But Finally I got solution from here https://stackoverflow.com/a/10775577/1115788 and I updated my code with padding as AES/CBC/PKCS5Padding and the same error is coming, and last block is not decrypted... I'm working on this for last two day, but no solution found my Crypter Code: package mani.droid.browsedropbox; import java.io.FileInputStream; import

Python爬取网易云音乐评论(附加密算法)

丶灬走出姿态 提交于 2019-11-29 00:50:19
网易云音乐,里面汇聚了哲学家,小说家,story-teller,皮皮虾等各种人才,某些评论非常值得收藏(甚至开了一个歌单专门收藏它们)。竟然这么好玩,何不尝试把他们爬取下来呢? 前置需求 可选:fiddler 捉包工具 (官网下载) 可选:了解一点AES,RSA加密 任一浏览器 pycryptodome模块 (直接pip安装) base64及binascii模块 (直接导入) 可选是指:如果你要深入了解如何找到加密方法,就选 结构分析 我们要爬的是歌曲的评论,而歌曲的来源有多种,有的来源于专辑,有的来源于歌单,有的来源于歌手页;而歌单和专辑的来源又有多种。所以爬取多个歌曲的评论之前,我们要分析一下信息的结构,最好写下来,这样头脑会更清晰减少代码修改量。这里放出一张我自己整理的结构,并选择一条线路来实现(发现音乐→→歌单→→歌曲→→评论) 至于上图所列的其他信息,读者可以过完这个实战后自己动手实现,但是要注意的是:某些信息是无法直接通过网页源码提取出来的,需要通过加密的动态包(其实是API)获得,如果有需要的话我可能会出一篇文章总结网易云音乐的API 收集歌单id 每个歌单都有唯一的id,通过http://music.163.com/playlist… 这个链接就可以找到歌单,所以第一步我们要收集发现音乐下的多个歌单id ''' 遇到不懂的问题?Python学习交流群

JavaScript AES encryption and decryption (Advanced Encryption Standard)

巧了我就是萌 提交于 2019-11-29 00:47:02
How to implement encryption and decryption using AES (Advanced Encryption Standard) in JavaScript. Why AES (Advanced Encryption Standard) ? Security: Competing algorithms were to be judged on their ability to resist attack, as compared to other submitted ciphers, though security strength was to be considered the most important factor in the competition. Cost: Intended to be released under a global, nonexclusive and royalty-free basis, the candidate algorithms were to be evaluated on computational and memory efficiency. function encrypt(message = '', key = ''){ var message = CryptoJS.AES