aes

前言 有些公司对接口的安全要求比较高，传参数的时候，不会明文的传输，先对接口加密，返回的数据也加密返回。 目前比较常见的加密方式是AES/CBC/pkcs7padding。 AES五种加密模式 在AES加密时，一般使用了“AES/ECB/NoPadding”或“AES/ECB/PKCS5padding” 或 “AES/ECB/PKCS5padding” 的模式 使用AES加密的ECB模式，显式指定加密算法为：CBC或CFB模式，可带上PKCS5Padding填充。AES密钥长度最少是128位，推荐使用256位 AES-ECB模式加密在加密和解密是需要一个初始化向量(Initialization Vector, IV)，在每次加密之前或者解密之后，使用初始化向量与明文或密文异或。 分组密码有五种工作体制： 1.电码本模式（Electronic Codebook Book (ECB)）； 2.密码分组链接模式（Cipher Block Chaining (CBC)）； 3.计算器模式（Counter (CTR)）； 4.密码反馈模式（Cipher FeedBack (CFB)）； 5.输出反馈模式（Output FeedBack (OFB)） AES算法是典型的【对称加密算法】，所谓对称加密，就是加密和解密的秘钥是一样的 JAVA加密 一般我们做接口自动化测试的时候

Is there a way to decompress an AES-128 encrypte file directly with python, since ZipFile throws a Bad Password error. If i use 7zip it works, so the password is correct, but then again 7zip needs to be installed as a dependency. What i tried: from ZipFile import ZipFile zip = ZipFile('test.zip') zip.extractall(pwd='password') This throws the Bad Password exception. Checking the file with 7zip 7z l -slt test.zip This returns: Encrypted = + Method = pkAES-128 Deflate The zipfile module from the Python standard library supports only CRC32 encrypted zip files (see here: http://hg.python.org

内容参考书： 深入浅出密码学——常用加密技术原理与应用 清华大学出版社 第四章 高级加密标准 AES的内部结构 AES是面向字节的密码： 假设状态A是由16个字节按照矩阵方式组成： 密钥K对应的矩阵是一样的形式。 字节代换层 如4-3图所示，每一轮的第一层都是字节代换层。 字节代换层可以看做是16个并行的s盒，每个s盒的输入和输出都是8位。 值得注意的是，AES使用的16个s盒是完全相同的 在这一层中，每个状态字节A i 都被替换为另一个字节B i ：S(A i )=B i s盒代换是一个双向映射，即256个可能的输入（8位）都与唯一的输出一一对应，这个属性允许我们唯一地逆转s盒，这也是解密操作所需要的。 s盒的数学描述： AES的s盒具有非常强的代数结构，可以看做一个两步的数学变换。 因为这部分和理解AES的实现关系不大，有兴趣可以看看原书，讲得很清楚。 在s盒的硬件实现部分，到底是用查找表来实现好，还是按部就班的计算好，这个问题先搁置，原书内容为： 扩散层 AES的扩散层由行移位和列混淆两个子层组成。扩散指的是将单个位的影响扩散到整个状态中。是线性操作。 行移位子层 行移位变换 循环往复地将状态矩阵的第二行向右移动三个字节，将第三行向右移动两个字节，将第四行向右移动一个字节，第一行保持不变 列混淆子层 如果将行移位之后的状态表示为B，列混淆后的输出状态表示为C

Today I learned that "password" tends to mean a memorizable string of an arbitrary number of characters, while "key" means a highly random string of bits (of a specific length based on the encryption algorithm used). And so today I first heard of the concept of a Key derivation function . I'm confused about how to derive a 32-byte key from a password of arbitrary length (in PHP). The following approach works but ignores the instruction of "[The salt] should be generated randomly" (so does Sodium ): $salt = 'this salt remains constant'; $iterations = 10; $length = 32; $aesKey = hash_pbkdf2(

package com.wondersgroup.netapply.util; import javax.crypto.Cipher; import javax.crypto.spec.IvParameterSpec; import javax.crypto.spec.SecretKeySpec; import org.apache.commons.codec.binary.Base64; public class AESutil { //AES加密 public static String Encrypt(String sSrc, String sKey) throws Exception { if (sKey == null) { return null; } // 判断Key是否为16位 if (sKey.length() != 16) { return null; } byte[] raw = sKey.getBytes(); SecretKeySpec skeySpec = new SecretKeySpec(raw, "AES"); Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");//"算法/模式/补码方式" IvParameterSpec iv = new IvParameterSpec(sKey

I'm quite new to C# so please be patient with me. I know this question was asked a lot if times, but I couldn't find an answer to my problem. I'm saving some data and before writing it to a file I convert it to binary and store it in array, which I encrypt and then write to file. I encrypt data in chunks (32 bytes). In the same way I read data in chunks of 32 bytes and then decrypt that data and then this should repeat till the end of file. But when it comes to decryption the following error is thrown: Padding is invalid and cannot be removed. I use the same key and iv (hardcoded just until I

I'm new to OpenSSL. I understand that encryption should be performed using the EVP API which acts as a common interface to all the ciphers. AES CTR mode seems to be present in the version of OpenSSL that I have, but the definition for EVP_aes_128_ctr is disabled in evp.h: #if 0 const EVP_CIPHER *EVP_aes_128_ctr(void); #endif Any idea why this is? Can I just remove the #if 0? Any other pointers on getting 128 bit AES CTR mode encryption to work in OpenSSL would be appreciated! Thanks! mindthief Btw, it looks like the answer to this is no, not yet. But maybe soon. I found this email thread

From this site I have this code snippet: >>> from Crypto.Cipher import AES >>> obj = AES.new('This is a key123', AES.MODE_CBC, 'This is an IV456') >>> message = "The answer is no" >>> ciphertext = obj.encrypt(message) >>> list(bytearray(ciphertext)) [214, 131, 141, 100, 33, 86, 84, 146, 170, 96, 65, 5, 224, 155, 139, 241] When I take this array and turn it into a String in Ruby and proceed to decrypt it, an error occurs: >> require 'openssl' => true >> obj2 = OpenSSL::Cipher::Cipher.new("AES-128-CBC") => #<OpenSSL::Cipher::Cipher:0x007fa388389b30> >> obj2.decrypt => #<OpenSSL::Cipher::Cipher

爬虫-网易云评论 # post请求体 params: HMtP7KwWWgctb71g3T8v7b5SzlO1qN5JDI6WC8AqPYoakAYrpw1hm99wsn0Hp6AfP1ZNlp494Z+4XGXKiYyEXYTSoHvYTVhYpgDxUuSBdgNcZE0IXkkoA5YUEnQf2ESWO3bmt09k2ogKLOoQNWxEnXRewB0Oy2lPEdo52CVVNkUTMMd/gVPq4Zhj4LUvyjDh encSecKey: 83e7a7f8bf53186b5c224d2732d86fb41a6366b8fb3c61b7dd4e630f6c5199e5c98732ab6fef399a8b4d08ece5a338e132c7cbc4a86a7f2d8c768431b408671acac04d05010406784afad5c36a904a784478bbc5a1fb29e46df26dc49fea70e6015d1a5409dec5a2f1bc0c997ffc3642177034138d7c2b9c872b35b81e95da7d # js文件中 var bLq2x = window.asrsea(JSON.stringify(i8a), bvc9T(["流泪", "强"]), bvc9T(TQ2x.md), bvc9T(["爱心", "女孩",