addressbook

Import Address Book from Gmail/Hotmail/Yahoo using C# and ASP.NET

由 我的未来我决定 提交于 2019-11-27 17:06:57
Hi can somebody tell me how to import all of my contacts from gmail, yahoo, hotmail and so on.. and i want to send an invitation for all my contacts? How can i achieve this? CMS Check the .NET Address Book API's of those providers: Google Contacts Data API Retrieving contacts (C#) Windows Live Contacts API Code samples (C#) Yahoo! Address Book API Yahoo! Web Service REST Calls (C#) Contacts API URI 来源： https://stackoverflow.com/questions/1085498/import-address-book-from-gmail-hotmail-yahoo-using-c-sharp-and-asp-net

ABPersonSetImageData Only Altering the Contact Thumbnail and Not the Full Pic

由 折月煮酒 提交于 2019-11-27 15:16:22
问题 I am trying to add a border around each contact photo. I have working code to create this bordered image and working code to set it as the contact image: if (image) { NSData *dataRef = UIImagePNGRepresentation(image); CFDataRef cfdata = CFDataCreate(NULL, [dataRef bytes], [dataRef length]); CFErrorRef error; ret = ABPersonSetImageData(person, cfdata, &error); if (ret) { ret = ABAddressBookSave(addressBook, &error); } else { DebugLog(@"Could not write the image to the person: %@", [error

Getting favourites contacts in Android

由 早过忘川 提交于 2019-11-27 11:43:39
I am trying to get all contacts in the favourites list of the Android contacts. Currently, I can get all the group ids including the favourite group ID. But it seems that there is no contacts that have the group ID as the favourite group ID. I'm trying to get All groups id and contacts in each group. After printing two list, I found that the group id of favorite is not in the contact list ArrayList<String> favGroupId=new ArrayList<String>(); final String[] GROUP_PROJECTION = new String[] { ContactsContract.Groups._ID, ContactsContract.Groups.TITLE }; Cursor cursor = getContentResolver().query(

Find Duplicate Elements In Array Using Swift

由 笑着哭i 提交于 2019-11-27 11:36:11
How to find Duplicate Elements in Array? I have array of phone numbers so in the phone numbers i should start searching from the right side to the left side and find similar 6 integers. then i should print them out. To find duplicates, you could build cross reference by phone number, then filter that down to duplicates only. For example, consider: let contacts = [ Contact(name: "Rob", phone: "555-1111"), Contact(name: "Richard", phone: "555-2222"), Contact(name: "Rachel", phone: "555-1111"), Contact(name: "Loren", phone: "555-2222"), Contact(name: "Mary", phone: "555-3333"), Contact(name:

ABAddressBookGetAuthorizationStatus in simulator always returns kABAuthorizationStatusAuthorized

由 一个人想着一个人 提交于 2019-11-27 08:09:37
问题 I am updating an app for iOS 6 Address Book authorization and have hit a problem in testing. The simulator always returns that authorization is granted. This means I do not see the dialog popup requesting permission and can therefore not test that code path. Ok, use a device instead... The problem there is the OS appears to remember my answer so only asks once. Deleting the app does not help. On reinstalling it has retained the permission setting from before, so again no popup. Resetting the

iPhone SDK: EXC_BAD_ACCESS with CFRelease for ABAddressBookRef

由 岁酱吖の 提交于 2019-11-27 06:24:02
问题 there's very strange error with my code.. In fact, there's no errors at all, just debugger starts with "Program received signal: “EXC_BAD_ACCESS”" message. Can anyone help me? I'm absolutely confused... Thank you. -(NSString *)fullNameForPhone:(NSString *)ph withAlternativeText:(NSString *)text { ABAddressBookRef addressBookRef = ABAddressBookCreate(); NSLog(@"create addressBookRef"); NSString *stringToReturn = text; CFArrayRef allPeopleRef = ABAddressBookCopyArrayOfAllPeople(addressBookRef);

How to get a CNContact phone number(s) as string in Swift?

由 百般思念 提交于 2019-11-27 05:32:49
问题 I am attempting to retrieve the names and phone number(s) of all contacts and put them into arrays with Swift in iOS. I have made it this far: func findContacts() -> [CNContact] { marrContactsNumber.removeAllObjects() marrContactsName.removeAllObjects() let store = CNContactStore() let keysToFetch = [CNContactGivenNameKey, CNContactFamilyNameKey, CNContactPhoneNumbersKey] let fetchRequest = CNContactFetchRequest(keysToFetch: keysToFetch) var contacts = [CNContact]() do { try store

Generate vCard from AddressBook.framework

由 谁说胖子不能爱 提交于 2019-11-27 05:16:03
问题 I'm utilising the AddressBook.framework in my iPhone app, and I'd like to replicate something along the lines of the share feature in Contacts.app. This basically attach's a specific contacts vCard to an email. As far as I know, there is nothing in the documentation that mentions generating a vCard. Is this a case of generating one myself? Or is there something available that can help me? 回答1: Totally agree with Dave DeLong's answer. Just want to add that since I simply wanted to create a

Creating a circularly linked list in C#?

由 一世执手 提交于 2019-11-27 04:30:20
What would be the best way to create a circularly linked list in C#. Should I derive it from the LinkedList< T> collection? I'm planning on creating a simple address book using this Linked List to store my contacts (it's gonna be a suck-y address book, but I don't care cause I'll be the only one to use it). I mainly just want to create the crucially linked list so that I can use it again in other projects. If you don't think the Linked List is the right way to go let me know which way would be better. Clueless As most of these answers don't actually get at the substance of the question, merely

Creating a circularly linked list in C#?

由 喜你入骨 提交于 2019-11-27 03:58:19
问题 What would be the best way to create a circularly linked list in C#. Should I derive it from the LinkedList< T> collection? I'm planning on creating a simple address book using this Linked List to store my contacts (it's gonna be a suck-y address book, but I don't care cause I'll be the only one to use it). I mainly just want to create the crucially linked list so that I can use it again in other projects. If you don't think the Linked List is the right way to go let me know which way would
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