accelerometer

Android Gyroscope verse Accelerometer

夙愿已清 提交于 2021-02-07 09:21:47
问题 I am building an Android game and I want to figure out whether the user tilts the device to the left or the right (Similar to how Temple Run works when you move the man from side to side). I have read many tutorials and examples and I made sample applications but the amount of data I get back from both the Gyroscope and the Accelerometer are overwhelming. Would I need both sets of hardware to work out whether the user tilts the device and in which direction? My current application is

Android Gyroscope verse Accelerometer

本小妞迷上赌 提交于 2021-02-07 09:19:05
问题 I am building an Android game and I want to figure out whether the user tilts the device to the left or the right (Similar to how Temple Run works when you move the man from side to side). I have read many tutorials and examples and I made sample applications but the amount of data I get back from both the Gyroscope and the Accelerometer are overwhelming. Would I need both sets of hardware to work out whether the user tilts the device and in which direction? My current application is

Access and use the values of the accelerometer in the Android kernel level

杀马特。学长 韩版系。学妹 提交于 2021-01-29 06:24:05
问题 How can I access the accelerometer in the android kernel space and use it's data? I'm working on a project where I need to control some of the phone's functionality while the phone is moving (in a car) and I want to use the accelerometer to help determine if the phone had accelerated. It has to all be done in the kernel space. I found on the android developer pages how to use the accelerometer and the SensorEvent to detect changes in a user level application. But how to do something like that

does the accelerometer work for the iphone/ipad simulator?

荒凉一梦 提交于 2020-12-06 06:43:50
问题 From what I can tell, my app should be firing accelerometer events while Im using the iPad simulator in XCode, but its not. I have googled around and it somewhat seems that the accelerometer is not implemented in the simulator, is this correct? If so, why on earth would they have a "Hardware->Shake Gesture" menu option? My code is as follows: .h file: @interface MyViewController : UIViewController <UIPickerViewDataSource, UIPickerViewDelegate, UIAccelerometerDelegate>{ UIAccelerometer

does the accelerometer work for the iphone/ipad simulator?

我们两清 提交于 2020-12-06 06:41:41
问题 From what I can tell, my app should be firing accelerometer events while Im using the iPad simulator in XCode, but its not. I have googled around and it somewhat seems that the accelerometer is not implemented in the simulator, is this correct? If so, why on earth would they have a "Hardware->Shake Gesture" menu option? My code is as follows: .h file: @interface MyViewController : UIViewController <UIPickerViewDataSource, UIPickerViewDelegate, UIAccelerometerDelegate>{ UIAccelerometer

Android get accelerometers on earth coordinate system

江枫思渺然 提交于 2020-12-02 10:34:03
问题 I'd like to get accelerometers on Android and have them on the earth coordinate system, just like on this topic Acceleration from device's coordinate system into absolute coordinate system or here Transforming accelerometer's data from device's coordinates to real world coordinates but these solutions don't work for me. I'm working on Processing. The project is simply to track the phones accelerations in space, no matter how it is (standing, on the side...). I'm new to Android too. I'd

Detect programmatically if iPhone is dropped using CoreMotion/Accelerometer

不想你离开。 提交于 2020-08-01 08:58:06
问题 So I am writing a piece of code where I have to detect different movement gestures using Accelerometer and gyroscope in iOS 4.3 above. Q1: Is there any existing opensource code which has achieved any movement/gesture detection? If not Q2: For now I want to detect if the iPhone is dropped. What I have achieved so far: CoreMotion API gives userAcceleration , which (afaik) is the acceleration that the user is giving to the device or the acceleration of device in some direction (x, y or z) with