32-bit

For the life of me I can't seem to find a working version of the Java SE JDK for a 32 bit Windows machine. Where did oracle put it? Thanks, Nathan Go on the Oracle website - the thing you are looking for is x86, not x32. You can pick whichever version of Java you need. The newest one is Java 7, but keep in mind that a lot of people are still using Java 6. I think it is an important skill (especially if you plan to do serious work with Java) to know how to maneuver in the Oracle website (and documentation) because you will be using it a lot. Try to avoid Google, and other mirror websites, it's

Originated from this question , I have this little F# code ( github ) to generate random values according to a normal distribution: // val nextSingle : (unit -> float32) let nextSingle = let r = System.Random() r.NextDouble >> float32 // val gauss : (float32 -> float32 -> seq<float32>) let gauss mean stdDev = let rec gauss ready = seq { match ready with | Some spare -> yield spare * stdDev + mean yield! gauss None | _ -> let rec loop () = let u = nextSingle() * 2.f - 1.f let v = nextSingle() * 2.f - 1.f let s = pown u 2 + pown v 2 if s >= 1.f || s = 0.f then loop() else u, v, s let u, v, s =

It appears that specifying the KEY_WOW64_64KEY flag ( reference ) when accessing a registry key under 32-bit Windows XP has no effect - that is, no error is thrown, and the key is opened as if you hadn't had the flag set. I know Windows 2000 throws an error when it encounters this flag. I want to make sure my app is compatible with as many versions of windows (2k and later) as possible. Is there a Microsoft reference that specifies each version of Windows' behaviour for this flag? In particular, I'd like something that validates my assumption that it has no effect at all on post-2k 32-bit

I need to set up the Git client on a cheap shared hosting, with a no-name 32-bit Linux distribution. GCC isn't available so I can't compile it on the server. I do have at my disposal 2 other 64-bit Linux servers and an OSX laptop which I could try to cross-compile a binary on. But I can't seem to get it to compile correctly; when I push the binaries to the 32-bit server it says it can't run the executable. It looks from other sources like I need to add "-arch i386" and/or "-m32" to the ./configure or make commands to work for 32-bit, but I guess I'm not using them correctly. Anyone know how to

I currently working with an old code that needs to run a 32-bit system. During this work I stumbled across an issue that (out of academic interest) I would like to understand the cause of. It seems that casting from float to int in 32-bit C behaves differently if the cast is done on a variable or on an expression. Consider the program: #include <stdio.h> int main() { int i,c1,c2; float f1,f10; for (i=0; i< 21; i++) { f1 = 3+i*0.1; f10 = f1*10.0; c1 = (int)f10; c2 = (int)(f1*10.0); printf("%d, %d, %d, %11.9f, %11.9f\n",c1,c2,c1-c2,f10,f1*10.0); } } Compiled (using gcc) either directly on a 32

Let's say I have a byte-stream in which I know the location of a 64-bit value (a 64-bit nonce). The byte-order is Little-Endian. As PHP's integer data-type is limited to 32-bit (at least on 32-bit operating systems) how would I convert the byte-sequence into a PHP numeric representation (float would be sufficient I think)? $serverChallenge = substr($bytes, 24, 8); // $serverChallenge now contains the byte-sequence // of which I know that it's a 64-bit value Stefan Gehrig Just looked up the code for Zend_Crypt_Math_BigInteger_Bcmath and Zend_Crypt_Math_BigInteger_Gmp which deals with this