How would I find the second largest salary from the employee table? [closed]

Answer 1

Try this:

select max(Emp_Sal) 
from Employee a
where 1 = ( select count(*) 
         from Employee b
         where b.Emp_Sal > a.Emp_Sal)

Answer 2

Maybe you should use DENSE_RANK.

SELECT *
FROM (
       SELECT
         [Salary],
         (DENSE_RANK()
         OVER
         (
           ORDER BY [Salary] DESC)) AS rnk
       FROM [Table1]
       GROUP BY [Num]
     ) AS A
WHERE A.rnk = 2

Answer 3

select max(sal) from emp
where sal not in (select max(sal) from emp )

OR

select max(salary) from emp table 
where sal<(select max(salary)from emp)

Answer 4

select max(Emp_Sal) 
from Employee a
where 1 = ( select count(*) 
         from Employee b
         where b.Emp_Sal > a.Emp_Sal)

Yes running man.

Answer 5

select * from emp 
where sal=(select min(sal) from 
(select sal from(select distinct sal from emp order by sal desc)
where rownum<=n));

n can be the value you want to see......

you can see all the fields of that person who having nth highest salary*strong text*

Answer 6

SELECT
    TOP 1 salary
FROM
    (
        SELECT
            TOP 2 salary
        FROM
            employees
    ) sal
ORDER BY
    salary DESC;