How would I find the second largest salary from the employee table? [closed]

Answer 1

Try this:

SELECT max(salary)
FROM emptable
WHERE salary < (SELECT max(salary)
                FROM emptable);

Answer 2

select max(Salary) from Employee 
where Salary
  not in (Select top4 salary from Employee);

because answer is as follows

max(5,6,7,8)

so 5th highest record will be displayed, first four will not be considered

Answer 3

Try something like:

SELECT TOP 1 compensation FROM (
  SELECT TOP 2 compensation FROM employees
  ORDER BY compensation DESC
) AS em ORDER BY compensation ASC

Essentially:

• Find the top 2 salaries in descending order.
• Of those 2, find the top salary in ascending order.
• The selected value is the second-highest salary.

If the salaries aren't distinct, you can use SELECT DISTINCT TOP ... instead.

Answer 4

select distinct(t1.sal) 
from emp t1 
where &n=(select count(distinct(t2.sal)) from emp t2 where t1.sal<=t2.sal);

Output: Enter value for n: if you want 2nd highest ,enter 2; if you want 5,enter n=3

Answer 5

   select * from compensation where Salary = (
      select top 1 Salary from (
      select top 2 Salary from compensation 
      group by Salary order by Salary desc) top2
      order by Salary)

which will give you all rows with second highest salary, which a few people may share

Answer 6

Try this:

SELECT
    salary,
    employeeid
FROM
    employees
ORDER BY
    salary DESC
LIMIT 2

Then just get the second row.