Java: how to initialize String[]?

Question

Error

% javac  StringTest.java 
StringTest.java:4: variable errorSoon might not have been initialized
        errorSoon[0] = \"Error, why?\"         


        

Answer 1

String[] string=new String[60];
System.out.println(string.length);

it is initialization and getting the STRING LENGTH code in very simple way for beginners

Answer 2

String[] args = new String[]{"firstarg", "secondarg", "thirdarg"};

Answer 3

In Java 8 we can also make use of streams e.g.

String[] strings = Stream.of("First", "Second", "Third").toArray(String[]::new);

In case we already have a list of strings (stringList) then we can collect into string array as:

String[] strings = stringList.stream().toArray(String[]::new);

Answer 4

You can always write it like this

String[] errorSoon = {"Hello","World"};

For (int x=0;x<errorSoon.length;x++) // in this way u create a for     loop that would like display the elements which are inside the array     errorSoon.oh errorSoon.length is the same as errorSoon<2 

{
   System.out.println(" "+errorSoon[x]); // this will output those two     words, at the top hello and world at the bottom of hello.  
}

Answer 5

I believe you just migrated from C++, Well in java you have to initialize a data type(other then primitive types and String is not a considered as a primitive type in java ) to use them as according to their specifications if you don't then its just like an empty reference variable (much like a pointer in the context of C++).

public class StringTest {
    public static void main(String[] args) {
        String[] errorSoon = new String[100];
        errorSoon[0] = "Error, why?";
        //another approach would be direct initialization
        String[] errorsoon = {"Error , why?"};   
    }
}