Java: how to initialize String[]?

Question

Error

% javac  StringTest.java 
StringTest.java:4: variable errorSoon might not have been initialized
        errorSoon[0] = \"Error, why?\"         


        

Answer 1

String[] errorSoon = { "foo", "bar" };

-- or --

String[] errorSoon = new String[2];
errorSoon[0] = "foo";
errorSoon[1] = "bar";

Answer 2

String Declaration:

String str;

String Initialization

String[] str=new String[3];//if we give string[2] will get Exception insted
str[0]="Tej";
str[1]="Good";
str[2]="Girl";

String str="SSN"; 

We can get individual character in String:

char chr=str.charAt(0);`//output will be S`

If I want to to get individual character Ascii value like this:

System.out.println((int)chr); //output:83

Now i want to convert Ascii value into Charecter/Symbol.

int n=(int)chr;
System.out.println((char)n);//output:S

Answer 3

String[] errorSoon = new String[n];

With n being how many strings it needs to hold.

You can do that in the declaration, or do it without the String[] later on, so long as it's before you try use them.

Answer 4

You need to initialize errorSoon, as indicated by the error message, you have only declared it.

String[] errorSoon;                   // <--declared statement
String[] errorSoon = new String[100]; // <--initialized statement

You need to initialize the array so it can allocate the correct memory storage for the String elements before you can start setting the index.

If you only declare the array (as you did) there is no memory allocated for the String elements, but only a reference handle to errorSoon, and will throw an error when you try to initialize a variable at any index.

As a side note, you could also initialize the String array inside braces, { } as so,

String[] errorSoon = {"Hello", "World"};

which is equivalent to

String[] errorSoon = new String[2];
errorSoon[0] = "Hello";
errorSoon[1] = "World";

Answer 5

You can use below code to initialize size and set empty value to array of Strings

String[] row = new String[size];
Arrays.fill(row, "");

Answer 6

String[] arr = {"foo", "bar"};

If you pass a string array to a method, do:

myFunc(arr);

or do:

myFunc(new String[] {"foo", "bar"});