How to remove first and last character of a string?

Question

I have worked in SOAP message to get LoginToken from Webservice, and store the LoginToken in String and used System.out.println(LoginToken); to print. This prin

Answer 1

this is perfectly working fine

String str = "[wdsd34svdf]";
//String str1 = str.replace("[","").replace("]", "");
String str1 = str.replaceAll("[^a-zA-Z0-9]", "");
System.out.println(str1);


String strr = "[wdsd(340) svdf]";
String strr1 = str.replaceAll("[^a-zA-Z0-9]", "");
System.out.println(strr1);

Answer 2

In Kotlin

private fun removeLastChar(str: String?): String? {
    return if (str == null || str.isEmpty()) str else str.substring(0, str.length - 1)
}

Answer 3

StringUtils's removeStart and removeEnd method help to remove string from start and end of a string.

In this case we could also use combination of this two method

String string = "[wdsd34svdf]";
System.out.println(StringUtils.removeStart(StringUtils.removeEnd(string, "]"), "["));

Answer 4

Try this to remove the first and last bracket of string ex.[1,2,3]

String s =str.replaceAll("[", "").replaceAll("]", "");

Exptected result = 1,2,3

Answer 5

This is generic solution:

str.replaceAll("^.|.$", "")

Answer 6

It's easy, You need to find index of [ and ] then substring. (Here [ is always at start and ] is at end) ,

String loginToken = "[wdsd34svdf]";
System.out.println( loginToken.substring( 1, loginToken.length() - 1 ) );