How to remove first and last character of a string?

Question

I have worked in SOAP message to get LoginToken from Webservice, and store the LoginToken in String and used System.out.println(LoginToken); to print. This prin

Answer 1

You can always use substring:

String loginToken = getName().toString();
loginToken = loginToken.substring(1, loginToken.length() - 1);

Answer 2

Another solution for this issue is use commons-lang (since version 2.0) StringUtils.substringBetween(String str, String open, String close) method. Main advantage is that it's null safe operation.

StringUtils.substringBetween("[wdsd34svdf]", "[", "]"); // returns wdsd34svdf

Answer 3

SOLUTION 1

def spaceMeOut(str1):

   print(str1[1:len(str1)-1])

str1='Hello'

print(spaceMeOut(str1))

SOLUTION 2

def spaceMeOut(str1):

  res=str1[1:len(str1)-1]

  print('{}'.format(res))

str1='Hello'

print(spaceMeOut(str1))

Answer 4

This will gives you basic idea

    String str="";
    String str1="";
    Scanner S=new Scanner(System.in);
    System.out.println("Enter the string");
    str=S.nextLine();
    int length=str.length();
    for(int i=0;i<length;i++)
    {
        str1=str.substring(1, length-1);
    }
    System.out.println(str1);

Answer 5

I had a similar scenario, and I thought that something like

str.replaceAll("\[|\]", "");

looked cleaner. Of course, if your token might have brackets in it, that wouldn't work.

Answer 6

This way you can remove 1 leading "[" and 1 trailing "]" character. If your string happen to not start with "[" or end with "]" it won't remove anything:

str.replaceAll("^\\[|\\]$", "")