Get title from YouTube videos

Question

I want to extract the Title of YouTube\'s videos. How can I do this?

Thanks.

Answer 1

Using JavaScript data API:

var loadInfo = function (videoId) {
    var gdata = document.createElement("script");
    gdata.src = "http://gdata.youtube.com/feeds/api/videos/" + videoId + "?v=2&alt=jsonc&callback=storeInfo";
    var body = document.getElementsByTagName("body")[0];
    body.appendChild(gdata);
};

var storeInfo = function (info) {
    console.log(info.data.title);
};

Then you just need to call loadInfo(videoId).

More informations are available on the API documentation.

Answer 2

Here's some cut and paste code for ColdFusion:

http://trycf.com/gist/f296d14e456a7c925d23a1282daa0b90

It works on CF9 (and likely, earlier versions) using YouTube API v3, which requires an API key.

I left some comments and diag stuff in it, for anyone who wants to dig deeper. Hope it helps someone.

Answer 3

Similarly to Matej M, but more simply:

import requests
from bs4 import BeautifulSoup


def get_video_name(id: str):
    """
    Return the name of the video as it appears on YouTube, given the video id.
    """
    r = requests.get(f'https://youtube.com/watch?v={id}')
    r.raise_for_status()
    soup = BeautifulSoup(r.content, "lxml")
    return soup.title.string


if __name__ == '__main__':
    js = get_video_name("RJqimlFcJsM")
    print('\n\n')
    print(js)

Answer 4

Hello In python3 i founded 2 ways

1) without API KEY

import urllib.request
import json
import urllib
import pprint

#change to yours VideoID or change url inparams
VideoID = "SZj6rAYkYOg" 

params = {"format": "json", "url": "https://www.youtube.com/watch?v=%s" % VideoID}
url = "https://www.youtube.com/oembed"
query_string = urllib.parse.urlencode(params)
url = url + "?" + query_string

with urllib.request.urlopen(url) as response:
    response_text = response.read()
    data = json.loads(response_text.decode())
    pprint.pprint(data)
    print(data['title'])

example results:

{'author_name': 'Google Developers',
 'author_url': 'https://www.youtube.com/user/GoogleDevelopers',
 'height': 270,
 'html': '<iframe width="480" height="270" '
         'src="https://www.youtube.com/embed/SZj6rAYkYOg?feature=oembed" '
         'frameborder="0" allow="autoplay; encrypted-media" '
         'allowfullscreen></iframe>',
 'provider_name': 'YouTube',
 'provider_url': 'https://www.youtube.com/',
 'thumbnail_height': 360,
 'thumbnail_url': 'https://i.ytimg.com/vi/SZj6rAYkYOg/hqdefault.jpg',
 'thumbnail_width': 480,
 'title': 'Google I/O 101:  Google APIs: Getting Started Quickly',
 'type': 'video',
 'version': '1.0',
 'width': 480}
Google I/O 101:  Google APIs: Getting Started Quickly

2) Using Google API - required APIKEY

import urllib.request
import json
import urllib
import pprint

APIKEY = "YOUR_GOOGLE_APIKEY"
VideoID = "YOUR_VIDEO_ID"

params = {'id': VideoID, 'key': APIKEY,
          'fields': 'items(id,snippet(channelId,title,categoryId),statistics)',
          'part': 'snippet,statistics'}

url = 'https://www.googleapis.com/youtube/v3/videos'

query_string = urllib.parse.urlencode(params)
url = url + "?" + query_string

with urllib.request.urlopen(url) as response:
    response_text = response.read()
    data = json.loads(response_text.decode())
    pprint.pprint(data)
    print("TITLE: %s " % data['items'][0]['snippet']['title'])

example results:

{'items': [{'id': 'SZj6rAYkYOg',
            'snippet': {'categoryId': '28',
                        'channelId': 'UC_x5XG1OV2P6uZZ5FSM9Ttw',
                        'title': 'Google I/O 101:  Google APIs: Getting '
                                 'Started Quickly'},
            'statistics': {'commentCount': '36',
                           'dislikeCount': '20',
                           'favoriteCount': '0',
                           'likeCount': '418',
                           'viewCount': '65783'}}]}
TITLE: Google I/O 101:  Google APIs: Getting Started Quickly

Answer 5

Also can be Done By using scrapy module

just I am telling you the cmd lines

scrapy shell "https://www.youtube.com/channel/UCVPrNa-6fkLu4DVF2m_0n2A"

or use the Video link

then type

Out[1]: response.xpath("//h1/span/text()").getall()                                                                                                  
Out[1]: ['\n    Python Package Publishing (Part-2) | Setting up the Package\n  ']

Remember For this u need to install scrapy module

This is 100% working and by far the most easy way I found to get the title and all other description also.