Get title from YouTube videos

Question

I want to extract the Title of YouTube\'s videos. How can I do this?

Thanks.

Answer 1

using python i got itimport pafy url = "https://www.youtube.com/watch?v=bMt47wvK6u0" video = pafy.new(url) print(video.title)

Answer 2

// This is the youtube video URL: http://www.youtube.com/watch?v=nOHHta68DdU
$code = "nOHHta68DdU";
// Get video feed info (xml) from youtube, but only the title | http://php.net/manual/en/function.file-get-contents.php
$video_feed = file_get_contents("http://gdata.youtube.com/feeds/api/videos?v=2&q=".$code."&max-results=1&fields=entry(title)&prettyprint=true");
// xml to object | http://php.net/manual/en/function.simplexml-load-string.php
$video_obj = simplexml_load_string($video_feed);
// Get the title string to a variable
$video_str = $video_obj->entry->title;
// Output
echo $video_str;

Answer 3

If python batch processing script is appreciated: I used BeautifulSoup to easily parse the title from HTML, urllib to download the HTML and unicodecsv libraries in order to save all the characters from Youtube title.

The only thing you need to do is to place csv with single (named) column url with URLs of the Youtube videos in the same folder as the script is and name it yt-urls.csv and run the script. You will get file yt-urls-titles.csv containing the URLs and its titles.

#!/usr/bin/python

from bs4 import BeautifulSoup
import urllib
import unicodecsv as csv

with open('yt-urls-titles.csv', 'wb') as f:
    resultcsv = csv.DictWriter(f, delimiter=';', quotechar='"',fieldnames=['url','title'])
    with open('yt-urls.csv', 'rb') as f:
        inputcsv = csv.DictReader(f, delimiter=';', quotechar='"')
        resultcsv.writeheader()
        for row in inputcsv:
            soup = BeautifulSoup(urllib.urlopen(row['url']).read(), "html.parser")
            resultcsv.writerow({'url': row['url'],'title': soup.title.string})

Answer 4

I believe the best way is to use youTube's gdata, and then grab info from XML that is returned

http://gdata.youtube.com/feeds/api/videos/6_Ukfpsb8RI

Update: There is a newer API out now which you should use instead

https://developers.google.com/youtube/v3/getting-started

URL: https://www.googleapis.com/youtube/v3/videos?id=7lCDEYXw3mM&key=YOUR_API_KEY
     &fields=items(id,snippet(channelId,title,categoryId),statistics)&part=snippet,statistics

Description: This example modifies the fields parameter from example 3 so that in the API response, each video resource's snippet object only includes the channelId, title, and categoryId properties.

API response:

{
 "videos": [
  {
   "id": "7lCDEYXw3mM",
   "snippet": {
    "channelId": "UC_x5XG1OV2P6uZZ5FSM9Ttw",
    "title": "Google I/O 101: Q&A On Using Google APIs",
    "categoryId": "28"
   },
   "statistics": {
    "viewCount": "3057",
    "likeCount": "25",
    "dislikeCount": "0",
    "favoriteCount": "17",
    "commentCount": "12"
   }
  }
 ]
}

Answer 5

You can do using Json to get the all info about video

$jsonURL = file_get_contents("https://www.googleapis.com/youtube/v3/videos?id={Your_Video_ID_Here}&key={Your_API_KEY}8&part=snippet");
$json = json_decode($jsonURL);

$vtitle = $json->{'items'}[0]->{'snippet'}->{'title'};
$vdescription = $json->{'items'}[0]->{'snippet'}->{'description'};
$vvid = $json->{'items'}[0]->{'id'};
$vdate = $json->{'items'}[0]->{'snippet'}->{'publishedAt'};
$vthumb = $json->{'items'}[0]->{'snippet'}->{'thumbnails'}->{'high'}->{'url'};

I hope it will solve your problem.

Answer 6

JavaX now ships with this function. Showing a video's thumbnail and title, for example, is a two-liner:

SS map = youtubeVideoInfo("https://www.youtube.com/watch?v=4If_vFZdFTk"));
showImage(map.get("title"), loadImage(map.get("thumbnail_url")));

Example