How to print a linebreak in a python function?

Question

I have a list of strings in my code;

A = [\'a1\', \'a2\', \'a3\' ...]
B = [\'b1\', \'b2\', \'b3\' ...]

and I want to print them separated b

Answer 1

The newline character is actually '\n'.

Answer 2

You can print a native linebreak using the standard os library

import os
with open('test.txt','w') as f:
    f.write(os.linesep)

Answer 3

\n is an escape sequence, denoted by the backslash. A normal forward slash, such as /n will not do the job. In your code you are using /n instead of \n.

Answer 4

Also if you're making it a console program, you can do: print(" ") and continue your program. I've found it the easiest way to separate my text.

Answer 5

You have your slash backwards, it should be "\n"

Answer 6

All three way you can use for newline character :

'\n'

"\n"

"""\n"""