How to print a linebreak in a python function?

Question

I have a list of strings in my code;

A = [\'a1\', \'a2\', \'a3\' ...]
B = [\'b1\', \'b2\', \'b3\' ...]

and I want to print them separated b

Answer 1

for pair in zip(A, B):
    print ">"+'\n'.join(pair)

Answer 2

>>> A = ['a1', 'a2', 'a3']
>>> B = ['b1', 'b2', 'b3']

>>> for x in A:
        for i in B:
            print ">" + x + "\n" + i

Outputs:

>a1
b1
>a1
b2
>a1
b3
>a2
b1
>a2
b2
>a2
b3
>a3
b1
>a3
b2
>a3
b3

Notice that you are using /n which is not correct!