Convert seconds to hours, minutes, seconds

Question

How can I convert seconds to hours, minutes and seconds?

show_time() {
  ?????
}

show_time 36 # 00:00:36
show_time 1036 # 00:17:26
show_time 91925 # 25:32:0         


        

Answer 1

I couldn't get Vaulter's/chepner's code to work correctly. I think that the correct code is:

convertsecs() {
    h=$(($1/3600))
    m=$((($1/60)%60))
    s=$(($1%60))
    printf "02d:%02d:%02d\n $h $m $s
}

Answer 2

Simple one-liner

$ secs=236521
$ printf '%dh:%dm:%ds\n' $(($secs/3600)) $(($secs%3600/60)) $(($secs%60))
65h:42m:1s

With leading zeroes

$ secs=236521
$ printf '%02dh:%02dm:%02ds\n' $(($secs/3600)) $(($secs%3600/60)) $(($secs%60))
65h:42m:01s

With days

$ secs=236521
$ printf '%dd:%dh:%dm:%ds\n' $(($secs/86400)) $(($secs%86400/3600)) $(($secs%3600/60)) \
  $(($secs%60))
2d:17h:42m:1s

With nanoseconds

$ secs=21218.6474912
$ printf '%02dh:%02dm:%02fs\n' $(echo -e "$secs/3600\n$secs%3600/60\n$secs%60"| bc | xargs echo)
05h:53m:38.647491s

Based on https://stackoverflow.com/a/28451379/188159 but edit got rejected.

Answer 3

Using dc:

$ echo '12345.678' | dc -e '?1~r60~r60~r[[0]P]szn[:]ndZ2>zn[:]ndZ2>zn[[.]n]sad0=ap'
3:25:45.678

The expression ?1~r60~r60~rn[:]nn[:]nn[[.]n]sad0=ap does the following:

?   read a line from stdin
1   push one
~   pop two values, divide, push the quotient followed by the remainder
r   reverse the top two values on the stack
60  push sixty
~   pop two values, divide, push the quotient followed by the remainder
r   reverse the top two values on the stack
60  push sixty
~   pop two values, divide, push the quotient followed by the remainder
r   reverse the top two values on the stack
[   interpret everything until the closing ] as a string
  [0]   push the literal string '0' to the stack
  n     pop the top value from the stack and print it with no newline
]   end of string, push the whole thing to the stack
sz  pop the top value (the string above) and store it in register z
n   pop the top value from the stack and print it with no newline
[:] push the literal string ':' to the stack
n   pop the top value from the stack and print it with no newline
d   duplicate the top value on the stack
Z   pop the top value from the stack and push the number of digits it has
2   push two
>z  pop the top two values and executes register z if the original top-of-stack is greater
n   pop the top value from the stack and print it with no newline
[:] push the literal string ':' to the stack
n   pop the top value from the stack and print it with no newline
d   duplicate the top value on the stack
Z   pop the top value from the stack and push the number of digits it has
2   push two
>z  pop the top two values and executes register z if the original top-of-stack is greater
n   pop the top value from the stack and print it with no newline
[   interpret everything until the closing ] as a string
  [.]   push the literal string '.' to the stack
  n     pop the top value from the stack and print it with no newline
]   end of string, push the whole thing to the stack
sa  pop the top value (the string above) and store it in register a
d   duplicate the top value on the stack
0   push zero
=a  pop two values and execute register a if they are equal
p   pop the top value and print it with a newline

An example execution with the stack state after each operation:

    : <empty stack>
?   : 12345.678
1   : 1, 12345.678
~   : .678, 12345
r   : 12345, .678  # stack is now seconds, fractional seconds
60  : 60, 12345, .678
~   : 45, 205, .678
r   : 205, 45, .678  # stack is now minutes, seconds, fractional seconds
60  : 60, 205, 45, .678
~   : 25, 3, 45, .678
r   : 3, 25, 45, .678  # stack is now hours, minutes, seconds, fractional seconds

[[0]n]  : [0]n, 3, 25, 45, .678
sz  : 3, 25, 45, .678  # '[0]n' stored in register z

n   : 25, 45, .678  # accumulated stdout: '3'
[:] : :, 25, 45, .678
n   : 25, 45, .678  # accumulated stdout: '3:'
d   : 25, 25, 45, .678
Z   : 2, 25, 45, .678
2   : 2, 2, 25, 45, .678
>z  : 25, 45, .678  # not greater, so register z is not executed
n   : 45, .678  # accumulated stdout: '3:25'
[:] : :, 45, .678
n   : 45, .678  # accumulated stdout: '3:25:'
d   : 45, 45, .678
Z   : 2, 45, 45, .678
2   : 2, 2, 45, .678
>z  : 45, .678  # not greater, so register z is not executed
n   : .678  # accumulated stdout: '3:25:45'

[[.]n]  : [.]n, .678
sa  : .678  # '[.]n' stored to register a
d   : .678, .678
0   : 0, .678, .678
=a  : .678  # not equal, so register a not executed
p   : <empty stack>  # accumulated stdout: '3:25:45.678\n'

In the case of 0 fractional seconds:

    : 3, 25, 45, 0  # starting just before we begin to print

n   : 25, 45, .678  # accumulated stdout: '3'
[:] : :, 25, 45, .678
n   : 25, 45, .678  # accumulated stdout: '3:'
d   : 25, 25, 45, .678
Z   : 2, 25, 45, .678
2   : 2, 2, 25, 45, .678
>z  : 25, 45, .678  # not greater, so register z is not executed
n   : 45, .678  # accumulated stdout: '3:25'
[:] : :, 45, .678
n   : 45, .678  # accumulated stdout: '3:25:'
d   : 45, 45, .678
Z   : 2, 45, 45, .678
2   : 2, 2, 45, .678
>z  : 45, .678  # not greater, so register z is not executed
n   : .678  # accumulated stdout: '3:25:45'

[[.]n]  : [.]n, 0
sa  : 0  # '[.]n' stored to register a
d   : 0, 0
0   : 0, 0, 0
=a  : 0  # equal, so register a executed
  [.] : ., 0
  n   : 0  # accumulated stdout: '3:35:45.'
p   : <empty stack>  # accumulated stdout: '3:25:45.0\n'

In case of a minutes value less than 10:

    : 3, 9, 45, 0  # starting just before we begin to print

n   : 9, 45, .678  # accumulated stdout: '3'
[:] : :, 9, 45, .678
n   : 9, 45, .678  # accumulated stdout: '3:'
d   : 9, 9, 45, .678
Z   : 1, 9, 45, .678
2   : 2, 1, 9, 45, .678
>z  : 9, 45, .678  # greater, so register z is executed
  [0]   : 0, 9, 45, .678
  n     : 9, 45, .678  # accumulated stdout: '3:0' 
n   : 9, .678  # accumulated stdout: '3:09'
# ...and continues as above

EDIT: this had a bug where strings like 7:7:34.123 could be printed. I have modified it to print a leading zero if necessary.

Answer 4

For us lazy people: ready-made script available at https://github.com/k0smik0/FaCRI/blob/master/fbcmd/bin/displaytime :

#!/bin/bash

function displaytime {
  local T=$1
  local D=$((T/60/60/24))
  local H=$((T/60/60%24))
  local M=$((T/60%60))
  local S=$((T%60))
  [[ $D > 0 ]] && printf '%d days ' $D
  [[ $H > 0 ]] && printf '%d hours ' $H
  [[ $M > 0 ]] && printf '%d minutes ' $M
  [[ $D > 0 || $H > 0 || $M > 0 ]] && printf 'and '
  printf '%d seconds\n' $S
}

displaytime $1

Basically just another spin on the other solutions, but has the added bonus of suppressing empty time units (f.e. 10 seconds instead of 0 hours 0 minutes 10 seconds). Couldn't quite track down the original source of the function, occurs in multiple git repos..

Answer 5

t=12345;printf %02d:%02d:%02d\\n $((t/3600)) $((t%3600/60)) $((t%60)) # POSIX
echo 12345|awk '{printf "%02d:%02d:%02d",$0/3600,$0%3600/60,$0%60}' # POSIX awk
date -d @12345 +%T # GNU date
date -r 12345 +%T # OS X's date

If others were searching for how to do the reverse:

IFS=: read h m s<<<03:25:45;echo $((h*3600+m*60+s)) # POSIX
echo 03:25:45|awk -F: '{print 3600*$1+60*$2+$3}' # POSIX awk

Answer 6

This is old post ovbioius -- but, for those who might are looking for the actual time elapsed but in military format (00:05:15:22 - instead of 0:5:15:22 )

!#/bin/bash
    num=$1
    min=0
    hour=0
    day=0
    if((num>59));then
        ((sec=num%60))
        ((num=num/60))
            if((num>59));then
            ((min=num%60))
            ((num=num/60))
                if((num>23));then
                    ((hour=num%24))
                    ((day=num/24))
                else
                    ((hour=num))
                fi
            else
                ((min=num))
            fi
        else
        ((sec=num))
    fi
    day=`seq -w 00 $day | tail -n 1`
    hour=`seq -w 00 $hour | tail -n 1`
    min=`seq -w 00 $min | tail -n 1`
    sec=`seq -w 00 $sec | tail -n 1`
    printf "$day:$hour:$min:$sec"
 exit 0