Convert seconds to hours, minutes, seconds

Question

How can I convert seconds to hours, minutes and seconds?

show_time() {
  ?????
}

show_time 36 # 00:00:36
show_time 1036 # 00:17:26
show_time 91925 # 25:32:0         


        

Answer 1

I use the following function myself:

function show_time () {
    num=$1
    min=0
    hour=0
    day=0
    if((num>59));then
        ((sec=num%60))
        ((num=num/60))
        if((num>59));then
            ((min=num%60))
            ((num=num/60))
            if((num>23));then
                ((hour=num%24))
                ((day=num/24))
            else
                ((hour=num))
            fi
        else
            ((min=num))
        fi
    else
        ((sec=num))
    fi
    echo "$day"d "$hour"h "$min"m "$sec"s
}

Note it counts days as well. Also, it shows a different result for your last number.

Answer 2

All above is for bash, disregarding there "#!/bin/sh" without any bashism will be:

convertsecs() {
    h=`expr $1 / 3600`
    m=`expr $1  % 3600 / 60`
    s=`expr $1 % 60`
    printf "%02d:%02d:%02d\n" $h $m $s
}

Answer 3

#!/bin/sh

convertsecs() {
 ((h=${1}/3600))
 ((m=(${1}%3600)/60))
 ((s=${1}%60))
 printf "%02d:%02d:%02d\n" $h $m $s
}
TIME1="36"
TIME2="1036"
TIME3="91925"

echo $(convertsecs $TIME1)
echo $(convertsecs $TIME2)
echo $(convertsecs $TIME3)

For float seconds:

convertsecs() {
 h=$(bc <<< "${1}/3600")
 m=$(bc <<< "(${1}%3600)/60")
 s=$(bc <<< "${1}%60")
 printf "%02d:%02d:%05.2f\n" $h $m $s
}

Answer 4

on MacOSX 10.13 Slight edit from @eMPee584 's code to get it all in one GO (put the function in some .bashrc like file and source it, use it as myuptime. For non-Mac OS, replace the T formula by one that gives the seconds since last boot.

myuptime () 
{ 
    local T=$(($(date +%s)-$(sysctl -n kern.boottime | awk '{print $4}' | sed 's/,//g')));
    local D=$((T/60/60/24));
    local H=$((T/60/60%24));
    local M=$((T/60%60));
    local S=$((T%60));
    printf '%s' "UpTime: ";
    [[ $D > 0 ]] && printf '%d days ' $D;
    [[ $H > 0 ]] && printf '%d hours ' $H;
    [[ $M > 0 ]] && printf '%d minutes ' $M;
    [[ $D > 0 || $H > 0 || $M > 0 ]] && printf '%d seconds\n' $S
}

Answer 5

In one line :

show_time () {

    if [ $1 -lt 86400 ]; then 
        date -d@${1} -u '+%Hh:%Mmn:%Ss';
    else 
        echo "$(($1/86400)) days $(date -d@$(($1%86400)) -u '+%Hh:%Mmn:%Ss')" ;
    fi
}

Add days if exist.

Answer 6

The simplest way I know of:

secs=100000
printf '%dh:%dm:%ds\n' $(($secs/3600)) $(($secs%3600/60)) $(($secs%60))

Note - if you want days then just add other unit and divide by 86400.