Shell script to capture Process ID and kill it if exist [duplicate]

Answer 1

I use the command pkill for this:

NAME
       pgrep, pkill - look up or signal processes based on name and 
       other attributes

SYNOPSIS
       pgrep [options] pattern
       pkill [options] pattern

DESCRIPTION
       pgrep looks through the currently running processes and lists 
       the process IDs which match the selection criteria to stdout.
       All the criteria have to match.  For example,

              $ pgrep -u root sshd

       will only list the processes called sshd AND owned by root.
       On the other hand,

              $ pgrep -u root,daemon

       will list the processes owned by root OR daemon.

       pkill will send the specified signal (by default SIGTERM) 
       to each process instead of listing them on stdout.

If your code runs via interpreter (java, python, ...) then the name of the process is the name of the interpreter. You need to user the argument --full. This matches against the command name and the arguments.

Answer 2

Try the following script:

#!/bin/bash
pgrep $1 2>&1 > /dev/null
if [ $? -eq 0 ]
then
{
    echo " "$1" PROCESS RUNNING "
    ps -ef | grep $1 | grep -v grep | awk '{print $2}'| xargs kill -9
}
else
{
    echo "  NO $1 PROCESS RUNNING"
};fi

Answer 3

This works good for me.

PID=`ps -eaf | grep syncapp | grep -v grep | awk '{print $2}'`
if [[ "" !=  "$PID" ]]; then
  echo "killing $PID"
  kill -9 $PID
fi

Answer 4

You probably wanted to write

`ps -ef | grep syncapp | awk '{print $2}'`

but I will endorse @PaulR's answer - killall -9 syncapp is a much better alternative.

Answer 5

A lot of *NIX systems also have either or both pkill(1) and killall(1) which, allows you to kill processes by name. Using them, you can avoid the whole parsing ps problem.