Shell script to capture Process ID and kill it if exist [duplicate]

Answer 1

Actually the easiest way to do that would be to pass kill arguments like below:

ps -ef | grep your_process_name | grep -v grep | awk '{print $2}' | xargs kill

Hope it helps.

Answer 2

Kill -9 PID

should be

kill -9 $PID

see the difference?

Answer 3

#!/bin/sh

#Find the Process ID for syncapp running instance

PID=`ps -ef | grep syncapp 'awk {print $2}'`

if [[ -z "$PID" ]] then
--->    Kill -9 PID
fi

Not sure if this helps, but 'kill' is not spelled correctly. It's capitalized.

Try 'kill' instead.

Answer 4

This should kill all processes matching the grep that you are permitted to kill.

-9 means "Kill all processes you can kill".

kill -9 $(ps -ef | grep [s]yncapp | awk '{print $2}')

Answer 5

PID=`ps -ef | grep syncapp 'awk {print $2}'`

if [[ -z "$PID" ]] then
**Kill -9 $PID**
fi

Answer 6

Came across somewhere..thought it is simple and useful

You can use the command in crontab directly ,

* * * * * ps -lf | grep "user" |  perl -ane '($h,$m,$s) = split /:/,$F
+[13]; kill 9, $F[3] if ($h > 1);'

or, we can write it as shell script ,

#!/bin/sh
# longprockill.sh
ps -lf | grep "user" |  perl -ane '($h,$m,$s) = split /:/,$F[13]; kill
+ 9, $F[3] if ($h > 1);'

And call it crontab like so,

* * * * * longprockill.sh