Android ViewPager get the current View

Question

I have a ViewPager, and I\'d like to get the current selected and visible view, not a position.

1. getChildAt(getCurrentItem) returns wrong Vi

Answer 1

Try this

 final int position = mViewPager.getCurrentItem();
    Fragment fragment = getSupportFragmentManager().findFragmentByTag("android:switcher:" + R.id.rewards_viewpager + ":"
            + position);

Answer 2

During my endeavors to find a way to decorate android views I think I defined alternative solution for th OP's problem that I have documented in my blog. I am linking to it as the code seems to be a little bit too much for including everything here.

The solution I propose:

• keeps the adapter and the view entirely separated
• one can easily query for a view with any index form the view pager and he will be returned either null if this view is currently not loaded or the corresponding view.

Answer 3

I use this method with android.support.v4.view.ViewPager

View getCurrentView(ViewPager viewPager) {
        try {
            final int currentItem = viewPager.getCurrentItem();
            for (int i = 0; i < viewPager.getChildCount(); i++) {
                final View child = viewPager.getChildAt(i);
                final ViewPager.LayoutParams layoutParams = (ViewPager.LayoutParams) child.getLayoutParams();

                Field f = layoutParams.getClass().getDeclaredField("position"); //NoSuchFieldException
                f.setAccessible(true);
                int position = (Integer) f.get(layoutParams); //IllegalAccessException

                if (!layoutParams.isDecor && currentItem == position) {
                    return child;
                }
            }
        } catch (NoSuchFieldException e) {
            Log.e(TAG, e.toString());
        } catch (IllegalArgumentException e) {
            Log.e(TAG, e.toString());
        } catch (IllegalAccessException e) {
            Log.e(TAG, e.toString());
        }
        return null;
    }

Answer 4

Please check this

((ViewGroup))mViewPager.getChildAt(MyActivity.mViewPager.getCurrentItem()));

else verify this link.

Answer 5

viewpager.getChildAt(0)

this always returns my currently selected view. this worked for me but I don't know-how.

Answer 6

I had to do it more general, so I decided to use the private 'position' of ViewPager.LayoutParams

        final int childCount = viewPager.getChildCount();
        for (int i = 0; i < childCount; i++) {
            final View child = viewPager.getChildAt(i);
            final ViewPager.LayoutParams lp = (ViewPager.LayoutParams) child.getLayoutParams();
            int position = 0;
            try {
                Field f = lp.getClass().getDeclaredField("position");
                f.setAccessible(true);
                position = f.getInt(lp); //IllegalAccessException
            } catch (NoSuchFieldException | IllegalAccessException ex) {ex.printStackTrace();}
            if (position == viewPager.getCurrentItem()) {
                viewToDraw = child;
            }
        }