Android ViewPager get the current View

Question

I have a ViewPager, and I\'d like to get the current selected and visible view, not a position.

1. getChildAt(getCurrentItem) returns wrong Vi

Answer 1

I've figured it out. What I did was to call setTag() with a name to all Views/ListViews, and just call findViewWithTag(mytag), mytag being the tag.

Unfortunately, there's no other way to solve this.

Answer 2

Use an Adapter extending PagerAdapter, and override setPrimaryItem method inside your PagerAdapter.

https://developer.android.com/reference/android/support/v4/view/PagerAdapter.html

class yourPagerAdapter extends PagerAdapter
{
    // .......

    @Override
    public void setPrimaryItem (ViewGroup container, int position, Object object)
    {
        int currentItemOnScreenPosition = position;
        View onScreenView = getChildAt(position);
    }

    // .......

}

Answer 3

You can find fragment by system tag. It's work for me. I used it in OnMeasure function.

id - viewPager ID

position - fragment which you want to get

Important! You get this fragment if your fragment was created in adapter. So you must to check supportedFragmentManager.findFragmentByTag("android:switcher:" + id + ":" + position) nullify

You can get view like this:

supportedFragmentManager.findFragmentByTag("android:switcher:" + id + ":" + position).view

You shouldn't give custom tag in adapter

Answer 4

You can get the current element by accessing your list of itens from your adapter calling myAdapter.yourListItens.get(myViewPager.getCurrentItem()); As you can see, ViewPager can retrieve the current index of element of you adapter (current page).

If you is using FragmentPagerAdapter you can do this cast:

FragmentPagerAdapter adapter = (FragmentPagerAdapter)myViewPager.getAdapter();

and call

adapter.getItem(myViewPager.getCurrentItem());

This works very well for me ;)

Answer 5

If you do not have many pages and you can safely apply setOffscreenPageLimit(N-1) where N is the total number of pages without wasting too much memory then you could do the following:

public Object instantiateItem(final ViewGroup container, final int position) {      
    CustomHomeView RL = new CustomHomeView(context);
    if (position==0){
        container.setId(R.id.home_container);} ...rest of code

then here is code to access your page

((ViewGroup)pager.findViewById(R.id.home_container)).getChildAt(pager.getCurrentItem()).setBackgroundColor(Color.BLUE);

If you want you can set up a method for accessing a page

RelativeLayout getPageAt(int index){
    RelativeLayout rl =  ((RelativeLayout)((ViewGroup)pager.findViewById(R.id.home_container)).getChildAt(index));
    return rl;
}

Answer 6

is that your first activity on the screen or have you layered some above each other already?

try this:

findViewById(android.R.id.content).getRootView()

or just:

findViewById(android.R.id.content) 

also depending on what you want try:

((ViewGroup)findViewById(android.R.id.content)).getChildAt(0)