I\'m brand new to Erlang. How do you do modulo (get the remainder of a division)? It\'s % in most C-like languages, but that designates a comment in Erlang.
Several
In Erlang, 5 rem 3. gives 2, and -5 rem 3. gives -2. If I understand your question, you would want -5 rem 3. to give 1 instead, since -5 = -2 * 3 + 1.
5 rem 3.
2
-5 rem 3.
-2
-5 = -2 * 3 + 1.
Does this do what you want?
mod(X,Y) when X > 0 -> X rem Y; mod(X,Y) when X < 0 -> Y + X rem Y; mod(0,Y) -> 0.