iterator pattern - error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'std::string' [duplicate]

Answer 1

//#include 

You aren't including the header. You've commented out the include directive.

In the Visual C++ Standard Library implementation, std::string can be used when you include , but the operator<< overload that allows insertion of an std::string into an std::ostream is only included if you include the actual header.

If you want your code to be portable, you must include to use std::string; which Standard Library headers are included by other headers is implementation-defined.