iterator pattern - error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'std::string' [duplicate]

Answer 1

//#include <string>

You aren't including the <string> header. You've commented out the include directive.

In the Visual C++ Standard Library implementation, std::string can be used when you include <iostream>, but the operator<< overload that allows insertion of an std::string into an std::ostream is only included if you include the actual <string> header.

If you want your code to be portable, you must include <string> to use std::string; which Standard Library headers are included by other headers is implementation-defined.

Answer 2

This is a guess, but I would look at

while( iterator->hasNext() ) {
    MenuItem* menuItem = dynamic_cast< MenuItem* >( iterator->next() );
    std::cout << menuItem->getName();
    std::cout << menuItem->getPrice() << " -- ";
    std::cout << menuItem->getDescription() << std::endl;
}

try changing menuItem->getName() and menuItem->getDescription to charater arrays