Initializing a char pointer in C. Why considered dangerous? [duplicate]

Answer 1

String literals like "test" are read-only and so they cannot be modified. So any attempt to modify them will result in undefined behavior.

For example:

char *a = "test";
*a = 'b';

The *a = 'b'; is an undefined behavior.

So if you want to modify them then you need to use an array

char a[]="test";

So you can modify the "test" to "best" by doing the following:

a[0] = 'b';