SICP Exercise 1.3 request for comments

Question

I\'m trying to learn scheme via SICP. Exercise 1.3 reads as follow: Define a procedure that takes three numbers as arguments and returns the sum of the squares of the two la

Answer 1

Here's yet another way to do it:

#!/usr/bin/env mzscheme
#lang scheme/load

(module ex-1.3 scheme/base
  (define (ex-1.3 a b c)
    (let* ((square (lambda (x) (* x x)))
           (p (lambda (a b c) (+ (square a) (square (if (> b c) b c))))))
      (if (> a b) (p a b c) (p b a c))))

  (require scheme/contract)
  (provide/contract [ex-1.3 (-> number? number? number? number?)]))

;; tests
(module ex-1.3/test scheme/base
  (require (planet "test.ss" ("schematics" "schemeunit.plt" 2))
           (planet "text-ui.ss" ("schematics" "schemeunit.plt" 2)))
  (require 'ex-1.3)

  (test/text-ui
   (test-suite
    "ex-1.3"
    (test-equal? "1 2 3" (ex-1.3 1 2 3) 13)
    (test-equal? "2 1 3" (ex-1.3 2 1 3) 13)
    (test-equal? "2 1. 3.5" (ex-1.3 2 1. 3.5) 16.25)
    (test-equal? "-2 -10. 3.5" (ex-1.3 -2 -10. 3.5) 16.25)
    (test-exn "2+1i 0 0" exn:fail:contract? (lambda () (ex-1.3 2+1i 0 0)))
    (test-equal? "all equal" (ex-1.3 3 3 3) 18))))

(require 'ex-1.3/test)

Example:

$ mzscheme ex-1.3.ss
6 success(es) 0 failure(s) 0 error(s) 6 test(s) run
0