How to get the last day of the month?

Question

Is there a way using Python\'s standard library to easily determine (i.e. one function call) the last day of a given month?

If the standard library doesn\'t support

Answer 1

The simplest way is to use datetime and some date math, e.g. subtract a day from the first day of the next month:

import datetime

def last_day_of_month(d: datetime.date) -> datetime.date:
    return (
        datetime.date(d.year + d.month//12, d.month % 12 + 1, 1) -
        datetime.timedelta(days=1)
    )

Alternatively, you could use calendar.monthrange() to get the number of days in a month (taking leap years into account) and update the date accordingly:

import calendar, datetime

def last_day_of_month(d: datetime.date) -> datetime.date:
    return d.replace(day=calendar.monthrange(d.year, d.month)[1])

A quick benchmark shows that the first version is noticeably faster:

In [14]: today = datetime.date.today()

In [15]: %timeit last_day_of_month_dt(today)
918 ns ± 3.54 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

In [16]: %timeit last_day_of_month_calendar(today)
1.4 µs ± 17.3 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)