How to get the last day of the month?

Question

Is there a way using Python\'s standard library to easily determine (i.e. one function call) the last day of a given month?

If the standard library doesn\'t support

Answer 1

For me it's the simplest way:

selected_date = date(some_year, some_month, some_day)

if selected_date.month == 12: # December
     last_day_selected_month = date(selected_date.year, selected_date.month, 31)
else:
     last_day_selected_month = date(selected_date.year, selected_date.month + 1, 1) - timedelta(days=1)

Answer 2

from datetime import timedelta
(any_day.replace(day=1) + timedelta(days=32)).replace(day=1) - timedelta(days=1)

Answer 3

You can calculate the end date yourself. the simple logic is to subtract a day from the start_date of next month. :)

So write a custom method,

import datetime

def end_date_of_a_month(date):


    start_date_of_this_month = date.replace(day=1)

    month = start_date_of_this_month.month
    year = start_date_of_this_month.year
    if month == 12:
        month = 1
        year += 1
    else:
        month += 1
    next_month_start_date = start_date_of_this_month.replace(month=month, year=year)

    this_month_end_date = next_month_start_date - datetime.timedelta(days=1)
    return this_month_end_date

Calling,

end_date_of_a_month(datetime.datetime.now().date())

It will return the end date of this month. Pass any date to this function. returns you the end date of that month.

Answer 4

This is the simplest solution for me using just the standard datetime library:

import datetime

def get_month_end(dt):
    first_of_month = datetime.datetime(dt.year, dt.month, 1)
    next_month_date = first_of_month + datetime.timedelta(days=32)
    new_dt = datetime.datetime(next_month_date.year, next_month_date.month, 1)
    return new_dt - datetime.timedelta(days=1)

Answer 5

import datetime

now = datetime.datetime.now()
start_month = datetime.datetime(now.year, now.month, 1)
date_on_next_month = start_month + datetime.timedelta(35)
start_next_month = datetime.datetime(date_on_next_month.year, date_on_next_month.month, 1)
last_day_month = start_next_month - datetime.timedelta(1)

Answer 6

The easiest & most reliable way I've found so Far is as:

from datetime import datetime
import calendar
days_in_month = calendar.monthrange(2020, 12)[1]
end_dt = datetime(2020, 12, days_in_month)