C# rotate bitmap 90 degrees

Question

I\'m trying to rotate a bitmap 90 degrees using the following function. The problem with it is that it cuts off part of the image when the height and width are not equal.

Answer 1

I came across and with a little modification I got it to work. I found some other examples and noticed something missing that made the difference for me. I had to call SetResolution, if I didn't the image ended up the wrong size. I also noticed the Height and Width were backwards, although I think there would be some modification for a non square image anyway. I figured I would post this for anyone who comes across this like I did with the same problem.

Here is my code

private static void RotateAndSaveImage(string input, string output, int angle)
{
    //Open the source image and create the bitmap for the rotatated image
    using (Bitmap sourceImage = new Bitmap(input))
    using (Bitmap rotateImage = new Bitmap(sourceImage.Width, sourceImage.Height))
    {
        //Set the resolution for the rotation image
        rotateImage.SetResolution(sourceImage.HorizontalResolution, sourceImage.VerticalResolution);
        //Create a graphics object
        using (Graphics gdi = Graphics.FromImage(rotateImage))
        {
            //Rotate the image
            gdi.TranslateTransform((float)sourceImage.Width / 2, (float)sourceImage.Height / 2);
            gdi.RotateTransform(angle);
            gdi.TranslateTransform(-(float)sourceImage.Width / 2, -(float)sourceImage.Height / 2);
            gdi.DrawImage(sourceImage, new System.Drawing.Point(0, 0));
        }

        //Save to a file
        rotateImage.Save(output);
    }
}