C# rotate bitmap 90 degrees

Question

I\'m trying to rotate a bitmap 90 degrees using the following function. The problem with it is that it cuts off part of the image when the height and width are not equal.

Answer 1

The bug is in your first call to TranslateTransform:

g.TranslateTransform((float)b.Width / 2, (float)b.Height / 2);

This transform needs to be in the coordinate space of returnBitmap rather than b, so this should be:

g.TranslateTransform((float)b.Height / 2, (float)b.Width / 2);

or equivalently

g.TranslateTransform((float)returnBitmap.Width / 2, (float)returnBitmap.Height / 2);

Your second TranslateTransform is correct, because it will be applied before the rotation.

However you're probably better off with the simpler RotateFlip method, as Rubens Farias suggested.

Answer 2

I came across and with a little modification I got it to work. I found some other examples and noticed something missing that made the difference for me. I had to call SetResolution, if I didn't the image ended up the wrong size. I also noticed the Height and Width were backwards, although I think there would be some modification for a non square image anyway. I figured I would post this for anyone who comes across this like I did with the same problem.

Here is my code

private static void RotateAndSaveImage(string input, string output, int angle)
{
    //Open the source image and create the bitmap for the rotatated image
    using (Bitmap sourceImage = new Bitmap(input))
    using (Bitmap rotateImage = new Bitmap(sourceImage.Width, sourceImage.Height))
    {
        //Set the resolution for the rotation image
        rotateImage.SetResolution(sourceImage.HorizontalResolution, sourceImage.VerticalResolution);
        //Create a graphics object
        using (Graphics gdi = Graphics.FromImage(rotateImage))
        {
            //Rotate the image
            gdi.TranslateTransform((float)sourceImage.Width / 2, (float)sourceImage.Height / 2);
            gdi.RotateTransform(angle);
            gdi.TranslateTransform(-(float)sourceImage.Width / 2, -(float)sourceImage.Height / 2);
            gdi.DrawImage(sourceImage, new System.Drawing.Point(0, 0));
        }

        //Save to a file
        rotateImage.Save(output);
    }
}

Answer 3

What about this:

private void RotateAndSaveImage(String input, String output)
{
    //create an object that we can use to examine an image file
    using (Image img = Image.FromFile(input))
    {
        //rotate the picture by 90 degrees and re-save the picture as a Jpeg
        img.RotateFlip(RotateFlipType.Rotate90FlipNone);
        img.Save(output, System.Drawing.Imaging.ImageFormat.Jpeg);
    }
}