Remove duplicates from integer array

Question

I having a problem with coding this:

Write a static method named removeDuplicates that takes as input an array of integers and returns as a result a new

Answer 1

This is an interview question. Question : Remove Duplicates from an array in place :

public class Solution4 {
    public static void main(String[] args) {

           int[] a = {1,1,2,3,4,5,6,6,7,8};

          int countwithoutDuplicates =  lengthofarraywithoutDuplicates(a);
          for(int i = 0 ; i < countwithoutDuplicates ; i++) {
              System.out.println(a[i] + " ");
          }
    }

    private static int lengthofarraywithoutDuplicates(int[] a) {
        int countwithoutDuplicates = 1 ;
        for (int i = 1; i < a.length; i++) {
              if( a[i] != a[i-1]      ) {
                 a[countwithoutDuplicates++] = a[i]; 
              }//if
        }//for
        System.out.println("length of array withpout duplicates = >" + countwithoutDuplicates);
        return countwithoutDuplicates;

    }//lengthofarraywithoutDuplicates


}

In Python :

def lengthwithoutduplicates(nums):
    if not nums: return 0
    if len(nums) == 1:return 1
    # moving backwards from last element i.e.len(a) -1 to first element 0 and step is -1
    for i in range(len(nums)-1,0,-1):
      # delete the repeated element
        if nums[i] == nums[i-1]: del nums[i]
        # store the new length of the array without the duplicates in a variable
        # and return the variable
    l = len(a)      
    return l



a = [1, 1, 2, 3, 4, 5, 6, 6, 7, 8];

l = lengthwithoutduplicates(a)
for i in range(1,l):print(i)

In Python: list comprehension using enumerate

a = [1, 1, 2, 3, 4, 5, 6, 6, 7, 8]

aa = [ ch  for i, ch in enumerate(a) if ch not in a[:i] ]
print(aa) # output => [1, 2, 3, 4, 5, 6, 7, 8]