Remove duplicates from integer array

Question

I having a problem with coding this:

Write a static method named removeDuplicates that takes as input an array of integers and returns as a result a new

Answer 1

hey all you can use this code that i create!!!

import java.util.*;

public class DistinctNumber {
    public static void main(String[] args) {

        int[] nums=  {1,3,2,3,4,3,2,5,4,6}; 
        int [] T2 = duplicate(nums);
        for (int i = 0; i < T2.length; i++) {
            System.out.println(T2[i]);

        } 
    }
    public static boolean exist(int x,int []A){
        for (int i = 0; i < A.length; i++) {
            if(x==A[i]){
                return true;
            }
        }
        return false;
    }
    public static int [] EliminateDuplicate(int [] numbers){
       int [] B = new int[numbers.length];
       int i=0,j=0;
       for(i=0;i<numbers.length;i++){
           if(!exist(numbers[i], B)){
               B[j] = numbers[i];
               j++;
           }

       }
       int[] C = new int[j];
        for (int k = 0; k < C.length; k++) {
            C[k] = B[k];

        }
       return C;
    }


}

Answer 2

public class Foo {

public static void main(String[] args) {
    //example input
    int input[] = new int[]{1, 6 , 5896, 5896, 9, 100,7, 1000, 8, 9, 0, 10, 90, 4};
    //use list because the size is dynamical can change
    List<Integer> result = new ArrayList<Integer>();

    for(int i=0; i<input.length; i++)
    {
        boolean match = false;
        for(int j=0; j<result.size(); j++)
        {
            //if the list contains any input element make match true
            if(result.get(j) == input[i])
                match = true;
        }
        //if there is no matching we can add the element to the result list
        if(!match)
            result.add(input[i]);
    }
    // Print the result
    for(int i=0; i<result.size(); i++)
        System.out.print(result.get(i) + ", ");

}

} output: 1, 6, 5896, 9, 100, 7, 1000, 8, 0, 10, 90, 4,

Answer 3

First of all, you should know length without duplicates(dups): initial length minus number of dups. Then create new array with right length. Then check each element of list[] for dups, if dup founded - check next element, if dup not founded - copy element to new array.

public static int[] eliminateDuplicates(int[] list) {
    int newLength = list.length;
    // find length w/o duplicates:
    for (int i = 1; i < list.length; i++) {
        for (int j = 0; j < i; j++) {
            if (list[i] == list[j]) {   // if duplicate founded then decrease length by 1
                newLength--;
                break;
            }
        }
    }

    int[] newArray = new int[newLength]; // create new array with new length
    newArray[0] = list[0];  // 1st element goes to new array
    int inx = 1;            // index for 2nd element of new array
    boolean isDuplicate;

    for (int i = 1; i < list.length; i++) {
        isDuplicate = false;
        for (int j = 0; j < i; j++) {
            if (list[i] == list[j]) {  // if duplicate founded then change boolean variable and break
                isDuplicate = true;
                break;
            }
        }
        if (!isDuplicate) {     // if it's not duplicate then put it to new array
            newArray[inx] = list[i];
            inx++;
        }
    }
    return newArray;
}

Answer 4

public class Test 
static int[] array = {4, 3, 3, 4, 5, 2, 4};
static HashSet list = new HashSet();
public static void main(String ar[])
{       
    for(int i=0;i<array.length;i++)
    {         
      list.add(array[i]);

    }
    System.out.println(list);
}}

The Output is : [2, 3, 4, 5]

Answer 5

You can use HashSet that does not allow dulplicate elements

public static void deleteDups(int a []) {

    HashSet<Integer> numbers = new HashSet<Integer>();

        for(int n : a)
        {
            numbers.add(n);
        }

        for(int k : numbers)
        {
            System.out.println(k);
        }
        System.out.println(numbers);
    }       

public static void main(String[] args) {
    int a[]={2,3,3,4,4,5,6};
            RemoveDuplicate.deleteDups(a);

}

}
o/p is 2
3
4
5
6

[2, 3, 4, 5, 6]

Answer 6

To Preserve the ordering and to remove duplicates in the integer array, you can try this:

public void removeDupInIntArray(int[] ints){
    Set<Integer> setString = new LinkedHashSet<Integer>();
    for(int i=0;i<ints.length;i++){
        setString.add(ints[i]);
    }
    System.out.println(setString);
}

Hope this helps.