I want to take an integer and get its ordinal, i.e.:
1 -> \"First\"
2 -> \"Second\"
3 -> \"Third\"
...
Bohemians answer is very good but I recommend improving the error handling. With the original version of ordinal if you supply a negative integer an ArrayIndexOutOfBoundsException will be thrown. I think my version below is clearer. I hope the junit is also useful so it is not necessary to visually check the output.
public class FormattingUtils {
/**
* Return the ordinal of a cardinal number (positive integer) (as per common usage rather than set theory).
* {@link http://stackoverflow.com/questions/6810336/is-there-a-library-or-utility-in-java-to-convert-an-integer-to-its-ordinal}
*
* @param i
* @return
* @throws {@code IllegalArgumentException}
*/
public static String ordinal(int i) {
if (i < 0) {
throw new IllegalArgumentException("Only +ve integers (cardinals) have an ordinal but " + i + " was supplied");
}
String[] sufixes = new String[] { "th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th" };
switch (i % 100) {
case 11:
case 12:
case 13:
return i + "th";
default:
return i + sufixes[i % 10];
}
}
}
import org.junit.Test;
import static org.assertj.core.api.Assertions.assertThat;
public class WhenWeCallFormattingUtils_Ordinal {
@Test
public void theEdgeCasesAreCovered() {
int[] edgeCases = { 0, 1, 2, 3, 4, 5, 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 100, 101, 102, 103, 104, 111, 112,
113, 114 };
String[] expectedResults = { "0th", "1st", "2nd", "3rd", "4th", "5th", "10th", "11th", "12th", "13th", "14th",
"20th", "21st", "22nd", "23rd", "24th", "100th", "101st", "102nd", "103rd", "104th", "111th", "112th",
"113th", "114th" };
for (int i = 0; i < edgeCases.length; i++) {
assertThat(FormattingUtils.ordinal(edgeCases[i])).isEqualTo(expectedResults[i]);
}
}
@Test(expected = IllegalArgumentException.class)
public void supplyingANegativeNumberCausesAnIllegalArgumentException() {
FormattingUtils.ordinal(-1);
}
}