Is there a way in Java to convert an integer to its ordinal name?

Question

I want to take an integer and get its ordinal, i.e.:

1 -> \"First\"
2 -> \"Second\"
3 -> \"Third\"
...

Answer 1

private static String getOrdinalIndicator(int number) {
        int mod = number;
        if (number > 13) {
            mod = number % 10;
        }
        switch (mod) {
        case 1:
            return "st";
        case 2:
            return "nd";
        case 3:
            return "rd";
        default:
            return "th";
        }
    }

Answer 2

Another solution

public static String ordinal(int i) {
    int mod100 = i % 100;
    int mod10 = i % 10;
    if(mod10 == 1 && mod100 != 11) {
        return i + "st";
    } else if(mod10 == 2 && mod100 != 12) {
        return i + "nd";
    } else if(mod10 == 3 && mod100 != 13) {
        return i + "rd";
    } else {
        return i + "th";
    }
}

Pro: does not require an array to be initialized (less garbage)
Con: not a one-liner...

Answer 3

I got a long, complicated one but easy to understand the concept

private static void convertMe() {

    Scanner in = new Scanner(System.in);
    try {
        System.out.println("input a number to convert: ");
        int n = in.nextInt();

        String s = String.valueOf(n);
        //System.out.println(s);

        int len = s.length() - 1;
        if (len == 0){
            char lastChar = s.charAt(len);
            if (lastChar == '1'){
                System.out.println(s + "st");
            } else if (lastChar == '2') {
                System.out.println(s + "nd");
            } else if (lastChar == '3') {
                System.out.println(s + "rd");
            } else {
                System.out.println(s + "th");
            }
        } else if (len > 0){
            char lastChar = s.charAt(len);
            char preLastChar = s.charAt(len - 1);
            if (lastChar == '1' && preLastChar != '1'){ //not ...11
                System.out.println(s + "st");
            } else if (lastChar == '2' && preLastChar != '1'){ //not ...12
                System.out.println(s + "nd");
            } else if (lastChar == '3' && preLastChar != '1'){ //not ...13
                System.out.println(s + "rd");
            } else {
                System.out.println(s + "th");
            }
        }


    } catch(InputMismatchException exception){
        System.out.println("invalid input");
    }


}

Answer 4

Best and Simple way, Here we go:

import java.util.*;
public class Numbers 
{
    public final static String print(int num)
    {
        num = num%10;
        String str = "";
        switch(num)
        {
        case 1:     
            str = "st";
            break;
        case 2:     
            str = "nd";
            break;
        case 3:     
            str = "rd";
            break;
        default: 
            str = "th";             
        }
        return str;
    }

    public static void main(String[] args) 
    {
        Scanner sc = new Scanner(System.in);
        System.out.print("Enter a number: ");
        int number = sc.nextInt();
        System.out.print(number + print(number));
    }
}

Answer 5

public static String getOrdinalFor(int value) {
         int tenRemainder = value % 10;
         switch (tenRemainder) {
          case 1:
           return value+"st";
          case 2:
           return value+"nd";
          case 3:
           return value+"rd";
          default:
           return value+"th";
         }
        }

Answer 6

In 1 line:

public static String ordinal(int i) {
    return i % 100 == 11 || i % 100 == 12 || i % 100 == 13 ? i + "th" : i + new String[]{"th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"}[i % 10];
}