“function does not exist,” but I really think it does

问题:

Am I crazy or just plain dumb?

dev=# \df abuse_resolve  List of functions -[ RECORD 1 ]-------+------------------------------------------------------------------------------------------------------------------------------------ Schema              | public Name                | abuse_resolve Result data type    | record Argument data types | INOUT __abuse_id bigint, OUT __msg character varying Type                | normal  dev=# select abuse_resolve('30'::bigint);  ERROR:  function abuse_resolve(bigint) does not exist LINE 1: select abuse_resolve('30'::bigint);                ^ HINT:  No function matches the given name and argument types. You might need to add explicit type casts. 

Here's the CREATE FUNCTION, I've omitted the meat of the code, but that should be irrelevant:

CREATE OR REPLACE FUNCTION abuse_resolve(INOUT __abuse_id bigint, OUT __msg character varying) RETURNS record AS $_$ DECLARE     __abuse_status    VARCHAR; BEGIN  ...snip...     UPDATE abuse SET abuse_status    = __abuse_status,                        edate    = now(),                        closed_on = now()                  WHERE abuse_id        = __abuse_id;     __msg = 'SUCCESS'; END; $_$ LANGUAGE plpgsql SECURITY DEFINER; 

And just for giggles:

GRANT ALL ON FUNCTION abuse_resolve(INOUT __abuse_id, OUT __msg character varying) TO PUBLIC; GRANT ALL ON FUNCTION abuse_resolve(INOUT __abuse_id, OUT __msg character varying) TO myuser; 

That function seems like it exists. What could I be missing?

This is resolved, the answer is: I'm dumb. I had improperly defined the arguments originally, but my code was using the correct ones. There was an extra bigint that had no business being there.

回答1:

Well, something is odd. I did:

steve@steve@[local] =# create function abuse_resolve(inout __abuse_id bigint,                                out __msg text) returns record language plpgsql as                                $$ begin __msg = 'ok'; end; $$; CREATE FUNCTION steve@steve@[local] =# \df abuse_resolve List of functions -[ RECORD 1 ]-------+---------------------------------------- Schema              | so9679418 Name                | abuse_resolve Result data type    | record Argument data types | INOUT __abuse_id bigint, OUT __msg text Type                | normal  steve@steve@[local] =# select abuse_resolve('30'::bigint); -[ RECORD 1 ]-+-------- abuse_resolve | (30,ok) 

Have you had any other issues with this database? Can you copy it with dump/restore and try this on the new copy? Does explicitly qualifying the function name with the "public" schema help? Which version of PostgreSQL are you using?

update: sql function It also worked fine for me using:

create function abuse_resolve(inout __abuse_id bigint, out __msg text)   language sql as $$ select $1, 'ok'::text $$; 

回答2:

If you can and if is that problem. I recommend to use

"set search_path = mainSchemaName, secondOnes"  

to set correct schema where function is created or in a place where you call it directly specify the schema name

select schemaName.abuse_resolve('30'::bigint); 

回答3:

Try this syntax:

SELECT * FROM abuse_resolve('30'::bigint); 

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