RxJS: Splitting an array result from Observable.fromPromise

问题:

I'm using RxJS here and I can't seem to get over this seemingly simple issue.

rx.Observable     .from([1,2,3,54,3,22,323,23,11,2])     .distinct()     .subscribe(function next (x) {         console.log('Next');         console.log(x);     }, function error (x) {         console.log('Error');         console.log(x);     }, function completed () {         console.log('Completed');     }); 

The above code spits out each array item in order as expected.

rx.Observable     .fromPromise(getNumbers([1,2,3,54,3,22,323,23,11,2]))     .distinct()     .subscribe(function next (x) {         console.log('Next');         console.log(x);     }, function error (x) {         console.log('Error');         console.log(x);     }, function completed () {         console.log('Completed');     });  function getNumbers (nums) {     return new Promise(function (resolve, reject) {         resolve(nums);     }); } 

Here though I only get the full array (i.e. [ 1, 2, 3, 54, 3, 22, 323, 23, 11, 2 ]). Shouldn't RxJS be breaking the result apart? I'd hope it at least had some logic for this.

Thank you

回答1:

No it will not break them apart implicitly. If you want to split them use flatMap which will flatten the array:

 rx.Observable     .fromPromise(getNumbers([1,2,3,54,3,22,323,23,11,2]))     .flatMap(function(x) { return x; })     .distinct()     .subscribe(function next (x) {         console.log('Next');         console.log(x);     }, function error (x) {         console.log('Error');         console.log(x);     }, function completed () {         console.log('Completed');     }); 

文章来源: RxJS: Splitting an array result from Observable.fromPromise